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ziro4ka [17]
3 years ago
15

Doing science by inquiry always involves:​

Physics
1 answer:
givi [52]3 years ago
6 0
B: asking questions

(Hope this helps)
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Which one of the following crystal structures has the fewest slip directions and therefore the metals with this structure are ge
marta [7]

Answer:

HCP

Extra -> BCC the most, FCC between

Explanation:

4 0
4 years ago
A solid sphere of radius R is made of a metallic conductor. A hollow spherical shell of the same radius R is made of the same co
Harrizon [31]

1-2) They have same surface charge density

3-4) The metallic conductor has greatest surface charge density

Explanation:

1-2)

In a conductor, the charge carriers (mainly electrons) are free to move. Therefore, as a result, they tend to move at the largest possible distance from each other, because of the repulsive force that they exert on each other.

The configuration that maximize the distance between the charge carriers for a solid sphere of metallic conductor is the one in which all the electrons are on the surface, and they are equally spaced between each other. This means that for the solid sphere of radius R, the excess charge Q will be entirely spread over the surface of the sphere.

Similarly, the excess charge Q on the hollow spherical shell (which is also made of the same conducting material) will also be spread over the surface with the charge carriers at the maximum distance from each other. Therefore, the surface charge density for both objects will be

\sigma = \frac{Q}{4\pi R^2}

where R is the radius of the two spheres.

3-4)

In this case, the surface charge density on the two objects is different.

In fact, on the metallic sphere (conducting) the surface charge density is (as explained in part 1):

\sigma = \frac{Q}{4\pi R^2}

Hoever, the second sphere is made of an insulating material. In an insulator, the charge carriers are not free to move. If the initial charge Q is spread across the all sphere (which is not hollow), this means that some of the charge will actually also be inside the sphere. So the charge deposited on the surface, Q', will be less than the total charge Q. Therefore, the surface charge density will be

\sigma' = \frac{Q'}{4\pi R^2}

And since Q' < Q, this means that \sigma', so the conducting sphere has a greatest surface charge  density.

4 0
3 years ago
A Light spiral spring is loaded with
kakasveta [241]

Answer:

0.63 s

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 50 g

Extention (e) = 10 cm

Period (T) =?

Next, we obtained 50 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

50 g = 50 g × 1 Kg / 1000 g

50 g = 0.05 kg

Next, we shall convert 10 cm to m. This is illustrated below:

100 cm = 1 m

Therefore,

10 cm = 10 cm × 1 m / 100 cm

10 cm = 0.1 m

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass = 0.05 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = mg

F = 0.05 × 9.8

F = 0.49 N

Next, we shall determine the spring constant of the spring.

Extention (e) = 0.1 m

Force (F) = 0.49 N

Spring constant (K) =?

F = Ke

0.49 = K × 0.1

Divide both side by 0.1

K = 0.49 /0.1

K = 4.9 N/m

Finally, we shall determine the period as follow:

Mass = 0.05 Kg

Spring constant (K) = 4.9 N/m

Pi (π) = 3.14

Period (T) =?

T = 2π√(m/k)

T = 2 × 3.14 × √(0.05 / 4.9)

T = 6.28 × √(0.05 / 4.9)

T = 0.63 s

Thus, the period of oscillation is 0.63 s

4 0
3 years ago
The main part of the nuclear power plant is the ____. Where nuclear ____ reactions take place.
emmasim [6.3K]
Turbine an unclean fission
7 0
4 years ago
Read 2 more answers
The amount of heat per second conducted from the blood capillaries beneath the skin to the surface is 250 j/s. the energy is tra
marin [14]
Heat flux (i) = k.a.temp variation/d
i = 250 J/s or 250w ; d = 2.1 x 10^-3m ; A = 1.9m^2 ; K (Body Fat) = 0.2W/m.Kelvin ; Temp. Var. (Delta T) = ?

-> 250 = 0.2 x 1.9 x deltaT/2.1 x 10^-3
-> 250 x 2.1 x 10^-3 = 0.38 x deltaT
-> 525 x 10^-3 = 38x10^-2 x deltaT
-> deltaT = 525 x 10^-3/ 38 x 10^-2
-> deltaT = 13.81 x 10^(-3 - (-2))
-> deltaT = 13.81 x 10^-1
-> deltaT = 1.381 K
5 0
3 years ago
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