Answer:
1.85 m/s
102.438 m
Explanation:
From vector motion
The resultant velocity

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s
The distance covered is 229 m
Time = Distance / Speed

Distance = Speed of current × Time
Distance = 0.756×135.5 = 102.438 m
The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore
Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.

where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
![240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]](https://tex.z-dn.net/?f=240%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A%28%5Cfrac%7B1h%7D%7B3600s%7D%20%29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D66.67%5Bm%2Fs%5D)
Now replacing:
![66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]](https://tex.z-dn.net/?f=66.67%20%3D%200%20%2Ba%2A2%5C%5Ca%20%3D%2033.33%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
![925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]](https://tex.z-dn.net/?f=925000%3Dm%2A33.33%5C%5Cm%20%3D%20925000%2F33.33%5C%5Cm%20%3D%2027752.7%20%5Bkg%5D)
Acceleration I’m pretty sure
Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D