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HACTEHA [7]
3 years ago
7

Which equation represents a line that passes through (–2, 4) and has a slope of ?

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0

Answer: the answer is y - 4 = (x + 2)


Step-by-step explanation:


hjlf3 years ago
7 0

Answer:

a

Step-by-step explanation:

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Which of the choices best describes this arithmetic sequence?<br> -3, 1, 5, 9, 13,...
zloy xaker [14]

Answer:

Add by 4

Step-by-step explanation:

-3+4=1

1+4=5

5+4=9

9+4=13

3 0
2 years ago
9/16+5/12= help asap
navik [9.2K]

\frac{9}{16}  +  \frac{5}{12}  =  \frac{27}{48}  +  \frac{20}{48} =  \frac{47}{48}
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3 years ago
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Please help me solve this angle problem. It is due today!
Paul [167]
Answer: B
No explanation
7 0
3 years ago
Please I don’t know how to do this
Andru [333]

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somewhere on the y axis so ig -4,-2?

Step-by-step explanation:

6 0
2 years ago
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Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
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