In which quadrant of the coordinate graph does point R lie?
2 answers:
You might be interested in
<u>Answer</u>:
The vertices are:
A' = (-3, -3)
B' = (3, -3)
C' = (3, 3)
D' = (-3, 3)
The ratio of area of larger square to smaller square is 9:1
<u>Step-by-step explanation:</u>
Given:
A 2 x 2 square is centered at the origin.
So, the center of the square is (0, 0)
Since it is 2 x 2 square, the side of the square is 2 units.
So, the vertices of the 2 x 2 square are A (-1, -1), B(1, -1), C(1. 1), D(-1, 1)
The above square is dilated by a factor of 3.
Let's name the dilated square A'B'C'D'
To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.
A(-1, -1) = 3(-1, -1) = A'(-3, -3)
B(1, -1) = 3(1, -1) = B'(3, -3)
C(1, 1) = 3(1, 1) = C'(3, 3)
D(-1, 1) = 3(-1, 1) = D'(-3, 3)
To find the area of the small square
the side of the small square is 2 units
so the are of the small square is = 4 square units
To find the area of the larger square
lets find the side AB of the square using distance formula
=>
=>
=>
=>
=>
=>6
AB =6 units
In a square all the sides will be equal
Now the area of the larger square will be
36 square units
The ratio of larger square to smaller square is
=>36 : 4
=>9 : 1
Answer:
Step 1: Solve one of the equations for one of the variables. Let's solve the first equation for x
Thus, option A) is true.
The solution to the system of equations be:
Step-by-step explanation:
It is important to remember that when we solve the system of equations, the first step we need to do is to solve one of the equations for one of the variables.
Given the system of equations
Step 1: Solve one of the equations for one of the variables. Let's solve the first equation for x
Add y to both sides
Thus, option A) is true.
<u>NOW LET US SOLVE THE REMAINING PORTION</u>
to solve for y
For x = -1 + y
substitute y = 5
Thus, the solution to the system of equations be: