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2 years ago

The quadrilaterals JKLM and PQRS are similar.

Mathematics

1 answer:

AlladinOne [14]2 years ago

7 0

Answer:

x = 6.3

Step-by-step explanation:

since the quadrilaterals are similar then the ratios of corresponding sides are in proportion, that is

$\frac{QR}{KL}$ = $\frac{RS}{LM}$ ( substitute values )

$\frac{x}{7}$ = $\frac{3.6}{4}$ ( cross- multiply )

4x = 7 × 3.6 = 35.2 ( divide both sides by 4 )

x = 6.3

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There were 200 melons in a box and they were distributed to 3 children in the ratio of 4:3:3. The first child sold the melons at

Elena L [17]

Answer:

$460

Step-by-step explanation:

let the number of melons be x

4x + 3x + 3x = 200 melons

10x = 200 so, x will be 20

4x = 80 melons

3x = 60

amount made by 1st child = 80 × $2 = 160$

the remaining melons are 60 + 60 = 120

amount collected: they sold them in groups of 2 and each group was $5. so,

120÷2 × $5 = $300

total amount = 300 + 160 = $460.

6 0

4 years ago

Use △GHJ, where A, B, and C are midpoints of the sides.

trasher [3.6K]

The answer is 17 , i just know that’s it

3 0

3 years ago

Read 2 more answers

At noon, the high temperature was 54 degrees. During the course of the day, the temperature increased 8 degrees, decreased 3 deg

pychu [463]

Answer:

Step-by-step explanation:

Let's write out what we know:

Noon temp: 54

Over the day, the temperature:

increased 8, decreased 3, increased 14, decreased 2, and decreased 10.

54+8-3+14-2-10 = 61

7 0

3 years ago

Please answer this for me correctly. THANK YOU!!

Leona [35]

Answer:

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5 0

3 years ago

a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora

Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is $6x+y=3500$ ..........[1]

When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is $4x+y=2400$ ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

$6x+y-4x-y=3500-2400$

$2x=1100$

$x=550$

Put value in [1],

$6(550)+y=3500$

$3300+y=3500$

$y=200$

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

8 0

3 years ago