Answer:
<h3>area of the slice:
A = 12π in² ≈ 37.7 in² </h3><h3>lenght of its crust:
L = 24π in ≈ 6.28 in</h3>
Step-by-step explanation:
R = 12 in
360°:30° = 12
so the area of the slice is ¹/₁₂ of whole pizza
A = ¹/₁₂•πR² = ¹/₁₂•π•12•12 = 12π in² ≈ 37.7 in²
Crust is the perimeter of pizza so crust of the slice is ¹/₁₂ of the perimeter:
L = ¹/₁₂•2πR = ¹/₁₂•2π•12 = 2π in ≈ 6.28 in
Answer: .320 is greater than .051 (use the > sign)
Step-by-step explanation:
too lazy to explain, but yes
Note: Consider we need to find each type of coins he has.
Given:
Erin has quarters and nickels for a total of 16 coins.
The value of his coins is $2.60.
To find:
The number of each type of coins.
Solution:
Let x represent the number of quarters and y represent the number of nickels.
According to the question,
Total coins :
...(i)
Total value :
...(ii)
Multiply equation (i) by 0.25 and subtract the result from (ii).



Divide both sides by -0.20.

Put y=7 in (i).



Therefore, the number of quarters is 9 and number of nickels is 7.
Answer:

For the variance we need to calculate first the second moment given by:

And replacing we got:

And the variance is given by:
![\sigma^2 = E(X^2) - [E(X)]^2 = 3.334 -[1.456]^2 =1.21](https://tex.z-dn.net/?f=%20%5Csigma%5E2%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2%20%3D%203.334%20-%5B1.456%5D%5E2%20%3D1.21)
And the deviation is:

Step-by-step explanation:
For thi case we have the following distribution given:
X 0 1 2 3 4 5
P(X) 0.207 0.367 0.227 0.162 0.036 0.001
For this case the expected value is given by:

And replacing we got:

For the variance we need to calculate first the second moment given by:

And replacing we got:

And the variance is given by:
![\sigma^2 = E(X^2) - [E(X)]^2 = 3.334 -[1.456]^2 =1.21](https://tex.z-dn.net/?f=%20%5Csigma%5E2%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2%20%3D%203.334%20-%5B1.456%5D%5E2%20%3D1.21)
And the deviation is:
