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alexdok [17]
3 years ago
14

What is the domain of the function

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

x\geq -6

Step-by-step explanation:

The domain of a function is all of the values that x can be under that specific function. In this case, we're asking what values of x allow \sqrt{\frac{1}{3} x+2} to exist.

In order for square roots to exist, the quantity under the square root must be greater than or equal to 0, because you can't take the square root of a negative number. Therefore, we can write the following inequality to solve for x:

\frac{1}{3}x+2\geq 0

Solving this inequality, we get:

\frac{1}{3}x+2\geq 0

\frac{1}{3}x\geq -2 (Subtract 2 from both sides of the inequality to isolate x)

x\geq -6 (Multiply both sides of the inequality by 3 to get rid of x's coefficient)

Hope this helps!

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konstantin123 [22]

Answer:

0.16/8.5

Step-by-step explanation:

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this means that the formula is

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6 0
3 years ago
Solve the inequality 12(1/2x-1/3)&gt;8-2x
gizmo_the_mogwai [7]

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d.x > 5/3

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3 years ago
1. Glenda is buying trees to plant in her yard. One tree that normally would cost $350 is on sale for 60% off.
butalik [34]

Answer:

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Hope this helps. Have a great day:)

3 0
2 years ago
Read 2 more answers
Is the given function continuous at x=1?
rusak2 [61]

Answer:

The answer is "Option C".

Step-by-step explanation:

Given:

\to f(x)=2x^2-3x+1\\\\when \ x=1\\\\\to f(1)= 2(1)^2-3(1)+1\\\\\to f(1)= 2(1)-3+1\\\\\to f(1)= 2-3+1\\\\\to f(1)=-1+1\\\\\to f(1)=0

That's why choice C is correct.

3 0
3 years ago
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Vinil7 [7]
I'm thinking this is what the problem looks like: \frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}.  The first thing to do is to move the \frac{x}{x-4} over to the other side because it has a common denominator with the other side.  Doing that and at the same time combining them over their common denominator looks like this: \frac{4-x}{x-4}= -\frac{4}{3}.  The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4).  Distributing through the parenthesis is 12 - 3x = -4x + 16.  Solving for x gives us x = 4.  Of course when we sub a 4 back in for x we get real problems, don't we?  Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.
6 0
3 years ago
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