Surface Area (SA) of a Cylinder formula:
SA = 2*pi*r*h+2*pi*r^2
If you fill in the formula:
SA = 2*3.14*2*9+2*3.14*2^2
Simplify:
SA = 6.28*18+6.28*4
SA = 113.04 + 25.12
SA = 138.16 in
I hope I helped
If its wrong I'm super duper extra sorry!
Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>
Answer: =−3/5
Step-by-step explanation: Hope this help :D
Answer:
=17
Step-by-step explanation:
We need the slope and the y-intercept to find the equation of the linear model.
This line goes through (0,28) and (1,26), so the slope is
\frac{26 - 28}{1} = -2
1
26−28
=−2
The equation that best describes this model is
\widehat{y} = -2x + 28
y
=−2x+28
Plug in x = 5.5 in the above equation to get
\widehat{y}
y
=−2x+28
=(−2)(5.5)+28
=−11+28
=17
Based on this equation, the date in April her flowers will bloom if the average temperature in March is
Answer:

Step-by-step explanation:
<u>Step 1: Find the square root of 81</u>
<u />



Answer: 