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never [62]
4 years ago
15

Which expression is equivalent to (2g^3+4)^2

Mathematics
2 answers:
babunello [35]4 years ago
7 0
(2g^3+4)^2= 4g^6 + 16g^3 + 16
The answer is B.
Marysya12 [62]4 years ago
5 0

Answer: b) 4g^6+16g^3+16


Step-by-step explanation:

Given expression: (2g^3+4)^2

Here (2g^3+4) is a binomial and square of a binomial must be a perct square trinomial.

Using pattern (a+b)^2=a^2+2ab+b^2

We get (2g^3+4)^2=(2g^3)^2+2(2g^3)(4)+4^2

=4g^{3\cdot2}+16g^3+16\\=4g^6+16g^3+16

Thus b) is the right option.

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Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
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For perpendicular lines m2 = -1/m1, i.e. the product of the two slopes equals -1.
x - 5y = 3
5y = x + 3
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m2 = -1/(1/5) = -5

Equation of a line containing point (-4, 6) with a slope of -5 is
y - 6 = -5(x - (-4))
y - 6 = -5(x + 4)
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4 years ago
What kind of symmetry does the toy have? A. rotational symmetry B. line symmetry C. both rotational and line symmetry D. neither
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3 years ago
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Step-by-step explanation:

4 0
3 years ago
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Step-by-step explanation:

6 0
3 years ago
Find the coordinates of the point of intersection of all parabolas that have equation y=x2+px +q with p+q=2020. The point of int
ioda

Answer:

(1,2021)

Step-by-step explanation:

P and q can vary subject to their sum being 2020.

Consider one parabola with p1 and q1 and another with p2 and q2.

y1=(x1)^2+(p1)(x1)+(q1)

y1=(x2)^2+(p2)(x2)+(q2)

At their intersection, the x and y coordinates are the same.

y1=y2=y

x1=x2=x

x^2+(p1)x+(q1)=x^2+(p2)x+(q2)

Solve for x

x(p1-p2)=q2-q1

x=(q2-q1)/(p1-p2)

Use the constraint that p+q=2020 to eliminate p1 and p2.

p1=2020-q1

p2=2020-q2

x=(q2-q1)/(2020-q1-2020+q2)

x=(q2-q1)/(q2-q1)

x=1

Substitute in the equation for y.

y=1^2+p(1)+q

y=2021

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3 years ago
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