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2 years ago

For each substance that can move across the dialysis membrane, determine whether it will move into the blood, out of the blood,

1 answer:

7 0

The movements of the substance across the dialysis membrane are as following: water: Moves in both directions.

Glucose: Moves into the blood.

Urea: Moves out of the blood.

Na, K, and Ca ions: Moves in both directions.

<h3>What is dialysis?</h3>

Dialysis is a process of filtration and purification of blood by a machine. This machine helped those people whose kidney stop working and doesn't purify the blood.

Thus, the correct options are: water: Moves in both directions.

Glucose: Moves into the blood.

Urea: Moves out of the blood.

Na, K, and Ca ions: Moves in both directions.

Learn more about dialysis

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Sodium is a larger atom than lithium. List three reasons why this is true.

just olya [345]

Answer:

It is present in third period that's why its valance electrons are present in 3rd energy level.

Its atomic number is greater than lithium when compared in group wise.

There are more electrons in sodium to shield the outer valance electron thus nuclear attraction becomes weak and size increase.

Explanation:

The size of sodium is greater than lithium because atomic number of sodium is 11 and lithium is 3. Both are present in first group but sodium is present down to the lithium. As we move from top to bottom in a group atomic size increases with addition of electrons. The nuclear effect become weaker on valance electrons and atomic size increase. Same time shielding effect is also produces which shield the outer electrons from the influence of nucleus. While in case of lithium less electrons are present to shield the valance electrons.

As we note the position of both elements along period. The sodium is present in third period while lithium is present in second period. So, in case of sodium third energy level is involved. That's why its size is greater than lithium.

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3 years ago

Recycled r134a refrigerant cannot exceed what levels of contaminants

Contact [7]

Answer is:
1) lubricant - 500 ppm by weight.
2) moisture - 50 ppm by weight.
3) non-condensable gases (air) - 150 ppm by weight.
Standard J2099 specific the maximum levels of contaminants for R134a.
ppm<span> (parts-per-million, </span>10⁻⁶) is <span>value that represents the part of a whole number in units of 1/1000000.</span>

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3 years ago

According to the big bang theory, which statement is accurate about how the universe came to be?

DIA [1.3K]

Answer:

The term Big Bang defines that the Universe has expanded from the ancient hot and thick primary situation at some fixed time in the past.

Big Bang theory refers to the origin of the Universe. In the beginning, universe is very heavy and small hot ball of matter. It was a point no bigger than the head of a pin when all the things squished with each other and universe is expanded with huge explosion of energy. Due to expansion, it is cooled and results in the formation of Stars and galaxies. After sometime, atoms formed like helium and hydrogen.

Thus, statement (1), (3) and (4) is correct whereas statement (2) and (5) is incorrect. the right answer is - (It expanded slowly), (Stars and galaxies formed,) (Atoms such as hydrogen and helium formed.)

Explanation:

8 0

3 years ago

Read 2 more answers

What is the formula of the compounds Cl- and Na+

Whitepunk [10]

Na and Cl together form the compound
NaCl2

5 0

3 years ago

Consider the balanced equation for the following reaction:

Zanzabum

<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 5.663 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8g}{32g/mol}=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $\frac{4}{7}\times 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.143mol\times 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}\times 100\\\\\text{Experimental yield of carbon dioxide}=\frac{90\times 6.292}{100}=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

7 0

3 years ago