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Lapatulllka [165]
4 years ago
5

HELP PLZ !!!! 20 POINTS !!!

Chemistry
2 answers:
xxMikexx [17]4 years ago
6 0
By all the resources many saw <span>Minnesota as a place to make business and get richer.</span>
Black_prince [1.1K]4 years ago
5 0
Made people Want to come and start a business <span />
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This lab question is: How can you distinguish a physical change from a chemical change?
geniusboy [140]

Answer:b,and c

Explanation:

4 0
3 years ago
A type of plate boundary that is transform faults (easily seen where they cut at right angles to the mid-ocean ridges) A.) conve
34kurt
The answer is Option C (Divergent Plate Boundary)

Mapping efforts have shown that mid-ocean ridges<span> are discontinuous structures that cut at </span>right angles<span> to its length at various transform faults. They typically </span><span>demarcate the </span>boundary <span>between two tectonic plates, and are therefore called </span>divergent<span> plate </span>boundaries.
8 0
3 years ago
Sodium-25 was to be used in an experiment, but it took 3.0 minutes to get the sodium from the reactor to the laboratory. If 8.0
Ksenya-84 [330]

Sodium-25 after 3 minutes : 1.0625 mg

<h3>Further explanation</h3>

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

<h3 />

No=8 mg

t1/2=60 s

T=3 min=180 s

\tt Nt=No\dfrac{1}{2}^{T/t1/2}\\\\Nt=8.5\dfrac{1}{2}^{180/60}\\\\Nt=8.5(\dfrac{1}{2})^3\\\\Nt=1.0625~mg

5 0
3 years ago
Help help help help help help​
natita [175]

Hey,

Answer:

<em>AgCl</em><em> </em>(Silver Chloride)

Explanation:

sodium chloride + silver nitrate → sodium nitrate+ silver chloride

Hope it helps :)

Have a great day!

3 0
3 years ago
In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co
12345 [234]

Answer:

650 mmol.

Explanation:

The equation for the fermentation of one mole of glucose is:

C₆H₁₂O₆ + 2 NAD⁺ + 2 ADP + 2 P i + 2 NADH → 2 EtOH + 2 ATP + 2 NADH + 2 NAD⁺

Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:

C₆H₁₂O₆ + 2 ADP + 2 P i  → 2 EtOH + 2 ATP

With the equation, we calculate the maximum amount of ethanol that could be obtained theoretically:

1000 mmol C₆H₁₂O₆ ------------ 2000 mmol EtOH

325 mmol C₆H₁₂O₆ ------------- x= 650 mmol EtOH

Therefore, the maximum amount of ethanol that could be produced is 650 mmol.

8 0
3 years ago
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