Question

On a recent quiz, the class mean was 72 with a standard deviation of 4.2. Calculate the z-score (to 2 decimal places) for a person who received score of 59.

Answer 1

Answer:

The Z score of the person is -3.09.

Step-by-step explanation:

The standard normal deviate (Z) for a normal distribution is given by

$Z=\frac{X-\bar{X}}{\sigma }$

where,

X = the value of observation

$\bar{X}$ is mean of the observations and

σ = standard deviation of the score

Applying values we get

$Z=\frac{59-72}{4.2}=-3.09$