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faltersainse [42]
3 years ago
11

On a recent quiz, the class mean was 72 with a standard deviation of 4.2. Calculate the z-score (to 2 decimal places) for a pers

on who received score of 59.
Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

The Z score of the person is -3.09.

Step-by-step explanation:

The standard normal deviate (Z) for a normal distribution is given by

Z=\frac{X-\bar{X}}{\sigma }

where,

X = the value of observation

\bar{X} is mean of the observations and

σ = standard deviation of the score

Applying values we get

Z=\frac{59-72}{4.2}=-3.09

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What’s the slope?................
Orlov [11]
M = y2-y1/x2-x1
m = 7- (-2)/ -6-(-7)
m = 9/1

slope = 9
7 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
which graph could represent y, the amount owed on a car loan, as regular payments are made each month, x?
lianna [129]

Answer is the second graph

The more payments you pay, the less money you owe.

4 0
3 years ago
Read 2 more answers
How do I find the inverse function of this equation
trapecia [35]

Answer:

y=ln(x/(1-x))

Step-by-step explanation:

y=e^x/(1+e^x)

Cross multiply

y(1+e^x)=e^x

Distribute

y+ye^x=e^x

Put anything with x on with side and everything without x on opposing side:

y=e^x-ye^x

Factor right hand side

y=(1-y)e^x

Divide both sides by (1-y)

y/(1-y)=e^x

Use natural log.

ln(y/(1-y))=x

The inverse is

y=ln(x/(1-x))

4 0
3 years ago
Is anyone good at statistics
masya89 [10]
Im taking stats right now i might be able to help.
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3 years ago
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