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3 years ago

Find the difference. m+2/(m-4)^2 - m-2/(m-4)^2

Mathematics

2 answers:

koban [17]3 years ago

5 0

Hi, i’ll do this question in 20 mins!

Lemur [1.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

Given

$\frac{m+2}{(m-4)^2}$ - $\frac{m-2}{(m-4)^2}$

Since the denominators are common then express as a single fraction

= $\frac{m+2-(m-2)}{(m-4)^2}$

= $\frac{m+2-m+2}{(m-4)^2}$

= $\frac{4}{(m-4)^2}$ → A

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3 years ago

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vladimir2022 [97]

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3 years ago

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3 years ago

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Digiron [165]

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3 years ago

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lina2011 [118]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}$

$\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt$

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3 years ago

Find the difference. m+2/(m-4)^2 - m-2/(m-4)^2​

Find the difference. m+2/(m-4)^2 - m-2/(m-4)^2