Question

If cos(beta)= -41/169 and

Answer 1

The value of the $sin 2\beta =\frac{-16 \sqrt {110}}{169}$. Option C is correct.

What is trigonometry?

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

Given;

cosβ=-41/169

$\rm sin \beta = \sqrt{1-cos^2\beta}\\\\ sin \beta = \sqrt{1-(\frac{-41}{169})^2} \\\\ sin \beta = \frac {163.95}{169}$

$\rm sin 2\beta = 2 sin \beta cos \beta \\\\ sin 2\beta = \frac{-41}{169} \times \frac{-41}{169} \\\\ sin 2\beta =\frac{-16 \sqrt {110}}{169}$

The value of the $sin 2\beta =\frac{-16 \sqrt {110}}{169}$.

Hence, option C is correct.

To learn more about trigonometry, refer to the link brainly.com/question/26719838

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