For the answer to the question above asking <span>what is the probability that a randomly selected student will be a boy that brings his lunch to school? I'll provide a solution for the following problem below.
</span>P(boy |lunch) = P(boy and lunch)/P(lunch) = 0.40
P(boy and lunch) = P(lunch)*0.4 = 0.3*0.4 = 0.12
4.75 Kilometers, you just divide by 1000
Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y

Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:





Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is 
6z-7z/5=3
(30z-7z)/5=3
30z-7z=15
23z=15
z=15/23