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timurjin [86]
3 years ago
5

I need help on number 6

Mathematics
1 answer:
taurus [48]3 years ago
7 0

Answer:

x = 0

Step-by-step explanation:

First we set up our equation. From the picture we can see that:

11 + x + 1 = 2x + 12

Now we can gather our like terms:

x + 12 = 2x + 12

Lets subtract x from both sides to isolate the x on the left:

12 = x + 12

Next we subtract 12 from both sides

x = 0

Check the answer

11 + 0 + 1 = 2(0) + 12

12 = 0 + 12

12 = 12

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What is the value of the expression
Y_Kistochka [10]

Answer:

0.8

Step-by-step explanation:

We begin with the expression: 0.5+(-\frac{3}{4} )+0.25-(-\frac{4}{5} )

First, we need to convert the fractions into decimals to make this easier.

-\frac{3}{4}=-0.75 and -\frac{4}{5} =-0.8

Once we have this, we can simplify it

0.5-0.75+0.25-(-0.8)\\\\0.5-0.75+0.25+0.8\\\\0.75-0.75+0.8\\\\0.8

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3 years ago
46 divided by 3652.4
kodGreya [7K]
46/3652.4=0.01259446
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3 years ago
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In a box of 720 pens,40% of the pens are blue. how many blue pens are there in the box?
romanna [79]

Answer:

<em><u>blue</u></em><em><u> </u></em><em><u>pens</u></em><em><u>=</u></em><em><u>288</u></em>

Step-by-step explanation:

<em>blue</em><em> </em><em>pens</em><em>=</em><em>720×40%</em>

<em>blue</em><em> </em><em>pens</em><em>=</em><em>720×40/100</em>

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I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

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3 years ago
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solniwko [45]

Answer:

True

Step-by-step explanation:

Example: 1.666666...

In that case, place the bar on top of the last 6

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