Answer:
Step-by-step explanation:
bsahaahaaana
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
Answer: 200x^2y+640x^2+1010xy+3232x-2380y-7616
Step-by-step explanation:
((8x−14)(5y+16))(5x+34)
((8x−14)(5y+16))(5x)+((8x−14)(5y+16))(34)
200x2y+640x2−350xy−1120x+1360xy+4352x−2380y−7616
200x2y+640x2+1010xy+3232x−2380y−7616
False, the image will be (+2; 5)
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