All categories

2 years ago

I need help with finding the limit for problem #1. I've already solved 2-4 I just don't get the first one.

Mathematics

1 answer:

emmainna [20.7K]2 years ago

7 0

Answer: 9

-------------------------------------------

Look at the graph of f(x). Locate x = 3 on the graph and move to the left of that location. If you get closer and closer to x = 3 from the left side, then you approach y = 3

Do the same for g(x) as well. If you approach x = 3 from the left, then you approach y = 3. It does not matter there is a discontinuity here as we're only worried about approaching x = 3 from the left and not actually getting to that specific x value.

We multiply those y values to get 3*3 = 9 as the answer

You might be interested in

What is the definition of symbolism?

notka56 [123]

Answer:

The use of symbols to represent ideas or qualities.

5 0

3 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$

$\ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}$

=> $\sigma = 8340$

Generally the test statistic is mathematically represented as

$t = \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }$

$t = -1.727$

From the z-table the p-value is

$p-value = P(Z > t) = P(Z > -1.727) = 0.95792$

From the values obtained we see that

$p-value > \alpha$ so we fail to reject the null hypothesis

Which implies that the claim of the NarStor is wrong

5 0

3 years ago

Algebra PLS HELP!!!!!!!!!!!!!

SCORPION-xisa [38]

Answer:

C - 53 Degrees

Step-by-step explanation:

4 0

2 years ago

Solve for x & y <br><br> plsssss, sorry.

andriy [413]

Answer:

$\huge\boxed{x=29;\ y=51}$

Step-by-step explanation:

This is Isosceles triangle (look at the picture).

We know:

All triangles have internal angles that add up to 180°

Therefore:

$(x-2)+(x-2)+(4x+10)=180$

combine like terms:

$(x+x+4x)+(-2-2+10)=180\\\\6x+6=180\qquad|\text{subtract 6 from both sides}\\\\6x=174\qquad|\text{divide both sides by 6}\\\\x=29$

(x - 2)° and 3y° are supplementary angle (Two Angles are Supplementary when they add up to 180°).

Therefore:

$3y+(x-2)=180$

substitute x = 29 and solve for y:

$3y+(29-2)=180\\\\3y+27=180\qquad|\text{subtract 27 from both sides}\\\\3y=153\qquad|\text{divide both sides by 3}\\\\y=51$

7 0

1 year ago

You spent 14 of your allowance on Monday. On Tuesday, you spent 13 of what was left. On Wednesday, you spent 12 of what remains.

Alex787 [66]

A = allowance
(1/2)a = what have left after Monday
(1/2(1/2)a = what you have after Tuesday
(1/2)(1/2)(1/2)a = what you have after Wednesday.

Doing the multiplication.

(1/8)a = what you have left.

You have 1/8 of what you had at the start.

5 0

1 year ago