I need help with finding the limit for problem #1. I've already solved 2-4 I just don't get the first one.

Mathematics

1 answer:

emmainna [20.7K]2 years ago

7 0

Answer: 9

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Look at the graph of f(x). Locate x = 3 on the graph and move to the left of that location. If you get closer and closer to x = 3 from the left side, then you approach y = 3

Do the same for g(x) as well. If you approach x = 3 from the left, then you approach y = 3. It does not matter there is a discontinuity here as we're only worried about approaching x = 3 from the left and not actually getting to that specific x value.

We multiply those y values to get 3*3 = 9 as the answer

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What is the vertex of (x) = –16x² + 64x + 80.

cricket20 [7]

Answer:

Step-by-step explanation:

f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)

$f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}$