<span>Let makes the table neater. event D= 100m, even E=800m
(Event D) (Event E)
A won the race (Event A) 30 50
B won the race (Event B) 60 25
A and B tied (Event T) 10 25</span>
B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%
The difference would be 75%-40%=35% more likely to lose 800-m race
Hello from MrBillDoesMath!
Answer: Yes, (8 1/2) /`17 = ( 17 11/12) /23
** I think you meant 11 1/2 is to 23 NOT 17 11 1/2 is to 23"
Discussion:
First, 8 1/2 = 17/2 and
(17/2
) / 17 = 1/2
Second 11 1/2 = 23/2 and
(23/2)/ 23 = 1/2
IN other words, the ratiors are the same:
8 1/2 11 1/2
------- = -------
17 23
Thank you,
MrB
The second 'p' is supposed to be 'e'. With that correction,
those letters can be unscrambled to spell " expand ".
Now it's your turn. Unscramble " Algerba ".
Answer:
22%
Step-by-step explanation:
Divide 2,650 by 100:
2,650/100=26.5
Then divide 3233 by the dividend:
122=122%
Now you can see that there is a 22% percent increase over 100%, theefore making our answer 22%.
Have a great day, and mark me brainliest if I am most helpful!