The equation for the area of a rhombus is
![A = \frac{ (d_1)( d_2)}{2}](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cfrac%7B%20%28d_1%29%28%20d_2%29%7D%7B2%7D%20)
, where
![d_1](https://tex.z-dn.net/?f=d_1)
and
![d_2](https://tex.z-dn.net/?f=d_2)
are the length of the diagonals of the rhombus, and A = area of the rhombus.
Your two diagonals are:
![d_1](https://tex.z-dn.net/?f=d_1)
= 5m + 5m = 10m
![d_2](https://tex.z-dn.net/?f=d_2)
= 10m + 10m = 20m
Plug these values into the equation for the area of a rhombus:
![A = \frac{ (d_1)( d_2)}{2} \\ A = \frac{ (10)(20)}{2} \\ A = \frac{200}{2} \\ A = 100m^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%20%28d_1%29%28%20d_2%29%7D%7B2%7D%20%5C%5C%0AA%20%3D%20%5Cfrac%7B%20%2810%29%2820%29%7D%7B2%7D%20%5C%5C%0AA%20%3D%20%20%5Cfrac%7B200%7D%7B2%7D%20%5C%5C%0AA%20%3D%20100m%5E2)
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Answer: 100
Answer:
89.95 inches.
Step-by-step explanation:
We are asked to find the best approximation for the perimeter of a semicircle whose diameter is 35 inches.
, where D represents diameter of semicircle.
Upon substituting D=35 and
in above formula we will get,
![\text{Perimeter of semicircle}=\frac{1}{2}\times 3.14\times 35+35](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20of%20semicircle%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%203.14%5Ctimes%2035%2B35)
![\text{Perimeter of semicircle}=3.14\times 17.5+35](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20of%20semicircle%7D%3D3.14%5Ctimes%2017.5%2B35)
![\text{Perimeter of semicircle}=54.95+35](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20of%20semicircle%7D%3D54.95%2B35)
![\text{Perimeter of semicircle}=89.95](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20of%20semicircle%7D%3D89.95)
Therefore, perimeter of our given semicircle is 89.95 inches.
Answer:
53.33
Step-by-step explanation:
finding area of ΔPAM
using similar triangles
![\frac{4}{x}= \frac{12}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%7D%3D%20%5Cfrac%7B12%7D%7B4%7D)
16 = 12x; x = ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
ΔPAM = 4/3 * 4 * 1/2 = 16/6 = 8/3
ΔPAL = 4 * 12 * 1/2 = 24
24 + 8/3 = 80/3 (using fraction form for now, will round later)
since there are two ΔPLM (ΔLMU has same area since they are congruent)
we can multiply 80/3 by 2
80/3 * 2 = 160/3 = 53.33
Answer:
The number of possible pictures:
N = 2 x 8 x 48 x 12 x 24 x 82 = 18137088
Hope this helps!
:)
38 people
They charge 8 dollars for one person and 3 dollars for every extra person 122-8=114
120/8=38