Solving a compound inequality for this solution gives solution as;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
<h3>How to solve inequality problems?</h3>
Let the number of daytime cameras be x
Let the number of flash cameras be y
Thus, we have;
x + y = 20 ------(1)
Now, daytime cameras costs 2.75 dollars and the flash camera costs 4.25 dollars and you want to spend between 65 and 75 dollars, inclusive. Thus, the inequality to represent this are;
2.75x + 4.25y ≥ 65 and 2.75x + 4.25y ≤ 75
Solving the 3 compound inequalities simultaneously, we can say that the approximate values of the numbers of cameras are;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
Read more about Inequalities at; brainly.com/question/25275758
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Answer:
Gallery: g
Balcony: 2g
Main floor: 2g+225
Step-by-step explanation:
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Answer: A(t) = (6.4 ft^2/min)*t
Step-by-step explanation:
We know that Emily paints at a constant rate, and she can paint 32 ft^2 in 5 minutes.
Then if we take the quotient of these two quantities, we will find the amount she can paint in one minute, this is:
32ft^2/5min = (32/5) ft^2/min = 6.4 ft^2/min.
Then if she paints for t minutes, the area that she can cover can be written as:
A(t) = (6.4 ft^2/min)*t
This is the linear equation we wanted to find.
$26.20 minimum cost of option 1
$36.68 minimum cost of option 2
Area₁ = Length x Width
A₁ = 80 x 36
A₁ = 2880 in² * this in only one side of the door.
Total Area = A₁ x 2 sides = 2880 = 5760 in² * only good for 1 coating of paint
Total Area to be coated = 5760 x 2 coats of paint = 11,520 in²
1st option - $10 / gallon and 4400 sq. in.
2nd option - $ 7 / gallon and 2200 sq. in
11,520 / 4400 = 2.62 x $10 = $26.20 minimum cost of option 1
11,520 / 2200 = 5.24 x $ 7 = $36.68 minimum cost of option 2