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vazorg [7]
3 years ago
7

Shanna's collection of antique pottery has increased in value over the past two years. Two years ago, the value of her collectio

n was $755. If the value increased 5% during the first year and 7% during the next year, what is the current value?
Mathematics
1 answer:
geniusboy [140]3 years ago
6 0
The current value is $848.24. I found the answer by, first multiplying $755 by 5% and adding $37.75 by $755. Next multiplying $792.75 by 7% and adding $55.49 by $792.75.
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What is the answer to this math problem?
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2 years ago
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4 years ago
The stadium is like a hemisphere with a radius of 150 feet last month the owners of the stadium paid 0. 05 per cubic foot to cov
GREYUIT [131]

The total cost for utilities last month is 353,571.43.

<h3>What is the total cost for utilities last month?</h3>

The total cost for utilities last month can be determined by multiplying the volume of the stadium by the cost per cubic foot.

The volume of the stadium can be determined by using the formula for the volume of a hemisphere.

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n = 22/7

r = radius

2/3 x 22/7 x 150³ = 7071,428.57

The total cost for utilities last month =  7071,428.57 x 0.05 = 353,571.43

To learn more about volume, please check: brainly.com/question/13705125

6 0
2 years ago
Convert the following sum into a product. cosx + cos3x + cos5x + cos7x
kvv77 [185]

Answer:

4\cos x\cos (4x)\cos (2x)

Step-by-step explanation:

Given: cosx + cos3x + cos5x + cos7x

To convert: the given sum into product

Solution:

Use formula: \cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)

4 0
3 years ago
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