Answer:
A red blood cell, sitting in the right atria of the heart is chocolate-brown in color since its a deoxygenated red blood cell with carbon dioxide rather than oxygen in its hemoglobin.
First
The tricuspid valve pumps it through the right ventricle
Secondly
pulmonary valve pumps it from the right ventricle to the pulmonary circulation.
Then
In the alveoli of the lungs, gas exchange occurs during pulmonary circulation
The end product is oxyhemoglobin( bright red colour) I.e oxygenated blood
The next step
pulmonary veins is the means whereby the red blood cell go to the left atria from the pulmonary circulation through the aortic valve
to mitral valve then to the aorta and systemic circulation
Therefore
oxygen is replaced by carbon dioxide during systemic circulation indicating a end to cellular respiration
Lastly
It's transported back to the right atrium of the heart completing the cardiac cycle.
1) To calculate the population density you first need to know how many <span>squirrels form that population.
To calculate the number of</span><span> squirrels:
1500</span> squirrels is the capacity, so it's equivalent to 100%
So how much squirrels are present in 80% of the area:
1500----100 %
x----------80 %
x= 1200 <span>squirrels
</span>
2)Population Density equals the number of squirrels divided by the land area
In the first part was calculated the number of squirrels and the exercise gives us the area in hectares so the only thing left to do is divide them.
(since this exercise doesn't specify that the area needs to be in a certain measurement we can use hectares)
Population Density = 1200/ 150
<span>The population density of the squirrels is 8 per hectare</span>
Answer:
Plants, animals and other organisms that live in deserts have evolved to survive harsh conditions, scarce water and barren landscapes. ... This desertification is exacerbated by human exploitation of ecosystems that border deserts, causing land degradation, soil erosion and sterility, and a loss of biodiversity.Explanation:
Answer:
a. autotriploid of species A: 63 chromosomes
b. autotetraploid of species B: 96 chromosomes
c. allotriploid from species A and B: 1) 66 chromosomes and 2) 69 chromosomes
Explanation:
<u>For a.</u>
this species will have 3 haploid sets of chromosomes ('tri' means 3)
one haploid set = 21
21 × 3 = 63 chromosomes
<u>For b.</u>
this species will have 4 haploid sets of chromosomes ('tetra' means 4)
one haploid set = 24
24 × 4 = 96 chromosomes
<u>For c.</u>
there are two ways to do this:
1) two sets of chromosomes from species A and one from species B
42 + 24 = 66 chromosomes
2) one set of chromosomes from species A and two from species B
21 + 48 = 69 chromosomes
Hope that answers the question, have a great day!
Q1. The answer is 53 chromosomes
Zebra has 44 diploid chromosomes (2n = 44). Zebra's gametes are haploid, so they will have 22 chromosomes (n = 22).
Donkey has 62 diploid chromosomes (2n = 62). Zebra's gametes are haploid, so they will have 31 chromosomes (n = 31).
After fusion of zebra's gamete (n = 22) and donkey's gamete (n = 31), the zonkey's zygote will have 22 + 31 = 53 chromosomes
Q2 and Q3. In the meiosis, the number of chromosomes is reduced by half. Since zonkey has 53 chromosomes, after meiosis it should have 53/2 chromosomes, which is not the whole number. This is the reason why they cannot produce normal gametes that will result, after the fusion, in the production of normal diploid zygote