I believe the answer is Monday!
Answer:
92 ft
Step-by-step explanation:
Assume the garden has the shape shown below.
The length of fencing equals the distance around three sides of the rectangle plus that around the semicircle.
1. Around the rectangle
Distance = 28 ft + 14 ft + 28 ft = 70 ft
2. Around the semicircle
For a circle.
C = 2πr
For the semicircle,
½C =½(2πr) = πr
D = 14 ft, so
r = 7 ft
3. Total distance
Distance = 70 ft + 22 ft = 92 ft
Jordan will need 92 ft of fencing.
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
The given expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%20%20%20)
This can be simplified using the radical properties as below
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20%20%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20)
Now using exponent properties we can write
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D2%5E%7B%5Cfrac%7B3-2%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B6%5D%7B2%7D%5C%5C%20)
Answer:
no
Step-by-step explanation:
From left to right, follow the dots in line 1 with your finger. Count a steady beat out loud, and time your motion so your finger crosses a dot at the end of each beat. Don’t pause at the dots, and move as smoothly as you can. A good way to count is to say or think “1 Mississippi, 2 Mississippi,” and so on. Is your finger moving at a constant rate, or is the rate changing?
