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3 years ago

8. It takes Olivia 3 | yards of ribbon

Mathematics

1 answer:

Leokris [45]3 years ago

7 0

Answer:

21 yards

Step-by-step explanation:

3 yards for 1 mum

3*7 yards for 7 mums

21 yards for 7 mums

I don't know if this is what you mean but here have this

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The legs of a right triangle are 3 units and 8 units. What is the length of the hypotenuse? Round your answer to the nearest hun

ASHA 777 [7]

Answer:

Step-by-step explanation:

Hypotenuse^2=3^2+8^2

Hypotenuse^2=9+64=73

Hypotenuse =square root of 73

Hypptenuse =8.54

5 0

3 years ago

A , B, C , D probability

BlackZzzverrR [31]

Answer:

your laptop is nice really

4 0

3 years ago

please help i will mark brainliest, no spam answers i will report.

vovikov84 [41]

9514 1404 393

Answer:

Step-by-step explanation:

Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...

CE : ED = 2 : 1

Try the answers with the x-coordinates.

CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect

CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect

CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct

CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect

The only viable choice is (3, 3).

_____

<em>Alternate solution</em>

For a partitioning of m : n, the desired point is ...

E = (n×C +m×D)/(m+n)

For partitioning of 2 : 1, the desired point is ...

E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3

E = (3, 3)

3 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

HIGHSCHOOL ALGEBRA!!!!! PLS HELP :) <br> Find the root of the equation: (6x–1)(6x+1) - 4x(9x+2) = −1

My name is Ann [436]

(6x–1)(6x+1) - 4x(9x+2) = −1

Simplify the left side:

36x^2-1 -36x^2-8x = -1

Combine like terms:

-1 -8x = -1

Add 1 to both sides:

-8x = 0

Divide both sides by -8:

x = 0 / -8

x = 0

The root is 0

5 0

4 years ago