We have been given the expression

We can rewrite the expression as 
In order to simplify the given expression, we can check if we have any common terms in the numerator and denominator.
We can write the term 72 which is in the numerator as 
Thus, the expression becomes

We can see that 4 is common in both numerator and denominator. Hence, we can cancel 4. Thus, we are left with

Therefore, we can rewrite the given expression as 54.
left means subtracting
6 7/8 - 2 5/8
Whole numbers subtract each other
Numerators subtract each other
The denominators stay the same.
6-2= 4
7-5=2
4 2/8
Reduce 2/8. Divide by 2. 2/2= 1, 8/2= 4
4 2/8=4 1/4
Answer: 4 2/8 = 4 1/4 cups left
When solving by substation the answer would be: X= 1 , y= 5
Answer:
→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>
→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>
→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>
Step-by-step explanation:
• let numbers be x, y and z

• from eqn 2, make x the subject:

• substitute all variables in eqn 3:

• find z

• find x:

Rounding to nearest value:

the answer is d
hope this helps