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2 years ago

A man works a basic week of 32 hours and earns $172.48. Find his basic rate of pay

Mathematics

1 answer:

kodGreya [7K]2 years ago

7 0

Answer:

$5.39/hour

Step-by-step explanation:

32 hours = 172.48

1 hour = 172.48 / 32

1 hour = 5.39

therefore, he earns $5.39/hour

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Factor the polynomial completely using any method. Show steps.<br> 2d^4-13d^2-45

Alinara [238K]

Answer:

$\huge ( {2d}^{2} + 5)(d + 3)(d - 3)$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

factoring
PEMDAS

<h3>given:</h3>

$2d^4-13d^2-45$

<h3>let's solve:</h3>

$2d^4-13d^2-45$

$2 {d}^{4} + 5 {d}^{2} - 18 {d}^{2} - 45 \\ {d}^{2} ( {2d}^{2} + 5) - 9( {2d}^{2} + 5) \\ ( {2d}^{2} + 5)( {d}^{2} - 9 )\\ ( {2d}^{2} + 5)(d + 3)(d - 3)$

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3 years ago

allison withdrew $7 from her savings account every day. if she continued to do this for a total of 5 days, find the integer that

AleksAgata [21]

Answer:

umm im not sure if this is the answer but i believe it would be -$35

Step-by-step explanation: -7 x 5

6 0

3 years ago

A farmer has 107 acres on which to plant oats or corn. Each acre of oats requires $18 capital and 2 hours of labor. Each acre of

Lera25 [3.4K]

Answer:

Step-by-step explanation:

the objective is to maximize profit

let x be corn and y be oat

let us begging by formulating the linear program for the problem

The objective function is

111x+47y=P

The constraints are

1. capital

36x+18y=2100------------1

2. labor

6x(8)+2y(8)=2400

48x+16y=2400-------------2

solving 1 and 2 we apply substitution method

36x+18y=2100------1

36x=2100-18y

x=(2100-18y)/36

put x=(2100-18y)/36 in 2 we have

48(2100-18y)/36+16y=2400

(100800-864y)/36+16y=2400

2800-24y+16y=2400

-8y=2400-2800

-8y=-400

8y=400

y=400/8

y=50

to find x put y=50 in 36x+18y=2100------------1

36x+18(50)=2100------------1

36x+900=2100

36x=2100-900

36x=1200

x=1200/36

x=33.33

profit is

111x+47y=P

111(33.33)+47(50)=P

3699.63+2350=P

P=6049.63

$6049.63

the planning comnination is to work on

33.33 acre of corn and 50 acre of oat

8 0

3 years ago

Evaluating integral by net area

N76 [4]

The graph of $f(x)=2$ is a horizontal line. So the area under $f(x)$ on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of $g(x)=\sqrt{64-x^2}$ is the upper half of a circle with radius $\sqrt{64}=8$ . It's symmetric about $x=0$ , so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is $\frac{\pi 8^2}4=16\pi$ .

Then use the fact that the definite integral is distributive over sums, meaning

$\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi$

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4 years ago

What is the slope of the line that passes through the points (1,-7) and (5,-25)?

Advocard [28]

The slope of the line is -9/2

8 0

3 years ago