Answer:
The amount of money in Enid bank account can be written as a linear equation.
Ye = Xe + $4*m
where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.
For Jim, the equation is similar:
Yj = Xj + $3*m
where Yj and Xj are similar as above.
Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).
Then we have that:
Ye = $72 = Xe + $4*7 = Xe + $28
Xe = $72 - $28 = $44
So in May 15, Enid deposited $44.
For Jim we have:
Yj = $72 = Xj + $3*7 = Xj + $21
Xj = $72 - $21 = $51
So in May 15, Jim deposited $51.
The answer is ae=12 that what i got right on my test
Answer:
Step-by-step explanation:
The first one as the first number must be >= 1 Here it is 0.2.
Answer:
the answer is 12 attendees
Step-by-step explanation:
Let a=the attendees & Let d=the cost
if the budget is $97 and the cost of the gala is represented by the equation d=7a+13, substitute the $97 for d
d=7a+13
97=7a+13
now take subtract 13 from both sides
97-13=7a+13-13
since the 13 cancels out on the right side it'll now read:
84=7a
to get a by itself you now divide 7 from both sides getting a by itself
84/7=7a/7
12=a
so the answer will be 12
