The table shows the number of the free throws each player made during the last basketball season determine if each statement is
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Using the information from the question, one can construct two equations:
... (1)
... (2)
by substituting (1) into (2) to find x
\frac{5}{4z} = \frac{1}{4}
⇒ z = 5
By substituting value of z into (1)
⇒ 4 (5) = x
⇒ x = 20
Thus the two numbers are 5 & 20
by substituting (1) into (2) to find x
\frac{5}{4z} = \frac{1}{4}
⇒ z = 5
By substituting value of z into (1)
⇒ 4 (5) = x
⇒ x = 20
Thus the two numbers are 5 & 20
Step-by-step explanation:
and
are two fractions that are greater than 1 but less than 2 with a denominator of 3;
The denominator is the lower number in a quotient
Numerator is the upper number in a quotient
To solve this problem, we need to think creatively:
A fraction is made up of a numerator and denominator.
The denominator in this case must be 3
The numerator can be any number;
since the solution of our fraction must be greater than 1, this implies that the numerator must higher than the denominator.
if the denominator is higher, we get a solution less than 1.
since the solution must be less than 2, the value lies between 1 and 2.
The solution to the problem is and
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