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marshall27 [118]
3 years ago
10

Would apreciate if someone helped me..

Mathematics
1 answer:
PtichkaEL [24]3 years ago
5 0

Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

e). m∠ADC = 18°

Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

and m∠DMC = 6x - 49

Since "in-center" of a triangle is a points where the bisectors of internal angles meet.

Therefore, MC is the angle bisector of angle AMD.

and m∠AMC ≅ m∠DMC

3x + 6 = 8x - 49

8x - 3x = 49 + 6

5x = 55

x = 11

b). m∠DMC = 8x - 49

                   = (8 × 11) - 49

                   = 88 - 49

                   = 39°

c). m∠MAD = 2(m∠DAC)

                   = 2(30)°

                   = 60°

d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

    2(39)° + m∠ADM + 66° = 180°

    78° + m∠ADM + 66° = 180°

    m∠ADM = 180° - 144°

                   = 36°

e). m∠ADC = \frac{1}{2}(m\angle ADM)

                   = \frac{1}{2}(36)

                   = 18°

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Answer:

Y' (5, -3), Z' (3, -2)

Step-by-step explanation:

The translation is right 4 and down 1.  Since you are going from (3, -4) to (7, -5), to get from 3 to 7 on the x axis you move right 4. To get from -4 to -5 on the y axis, you go down 1.

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3 years ago
Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
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Answer:

a) 0.4352

b) 0.5165

c) 0.0813

Step-by-step explanation:

In this problem we have 3 defective parts scattered among 15 parts.

We are going to select 3 out of 15 without replacement, so the situation can be modeled with the Hypergeometric distribution.

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This would be P(X=1)+P(X=2)+P(X=3) = 1 - P(X=0).  

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6 0
3 years ago
I need help on this problem
Arte-miy333 [17]

Answer: QR=4.04

Step-by-step explanation:

For this exercise you must use the followinG Trigonometric Identity:

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\alpha=60\°\\opposite=PR=7.0\\adjacent=QR

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And the final step is to solve for "QR" in order to find its value.

So you get that this is:

(QR)(tan(60\°))=7.0\\\\QR=\frac{7.0}{tan(60\°)}\\\\QR=4.04

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