Question

What is the max height of n=-1t^2+2t+8

Answer 1

The maximum height of the function is 9

How to determine the maximum height?

The equation of the function is given as:

n=-1t^2 + 2t + 8

Differentiate the function

n' = -2t + 2

Set to 0

-2t + 2 = 0

Subtract 2 from both sides

-2t = -2

Divide both sides by -2

t = 1

Substitute t = 1 in n=-1t^2 + 2t + 8

n=-1(1)^2 + 2(1) + 8

Evaluate

n=9

Hence, the maximum height of the function is 9

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