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3 years ago

Evaluate |-3| ±3 -3 3

Mathematics

2 answers:

enyata [817]3 years ago

8 0

Answ|-3| = 3er:

Step-by-step explanation:hope that helps

marin [14]3 years ago

4 0

Answer:

Its just 3

Step-by-step explanation:

Because its absolute value.

Hope this helps!

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The difference between two numbers is 12. Four times the larger number decreased by 25 equals 48 increased by 3 times the smalle

Lostsunrise [7]

Step-by-step explanation:

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Math

The difference between two numbers is 12. Three times the larger number is seven times the smaller. What are the two numbers?

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Expert Answers info

JEEW-M | CERTIFIED EDUCATOR

Let us say the two numbers are x and y and x>y.

The data we have are;

Difference between the numbers are 12.

3 times larger number is equal to 7 times smaller number.

Then we can write;

----(1)

----(2)

From (1) we can say

Then substituting to (2) gives;

Then;

7 0

3 years ago

The distance from Rodney's house to the park is 100 meters. If he walks to the park and back to his house, how far will he have

konstantin123 [22]

Answer:

c. 20,000cm

Step-by-step explanation:

from is house to the park is 100m

from the park back to his house is another 100m

100m+100m=200m

1m = 100cm

200m = xcm

cross multiply

xcm = 200×100

xcm= 20,000cm

3 0

3 years ago

(ANSWER FOR FREE BRAINPOINTS!) (FIRST TO ANSWER GETS BAINLIEST) The local park has a rectangular swimming pool that measures 40

iren [92.7K]

Answer:

9 yards

Step-by-step explanation:

Since both pools are similar, therefore the ratio of their length and width would be equal. That is:

Length of the current swimming pool : length of the new swimming pool = width of the current swimming pool : width of the new swimming pool

Thus, we can set up a proportion as shown below:

Let the width of the new swimming pool be x.

40 : 24 = 15 : x

$\frac{40}{24} = \frac{15}{x}$

Cross multiply

$40*x = 15*24$

$40x = 360$

Divide both sides by 40

$x = \frac{360}{40}$

$x = 9$

The width of the new swimming that is smaller would be 9 yards.

4 0

2 years ago

What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17

Pepsi [2]

IQR = 6

First locate the median $Q_{2}$ at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles $Q_{1}$ and $Q_{3}$ located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

↑

$Q_{2}$ = 18

$Q_{1}$ = $\frac{16+17}{2}$ = 16.5

$Q_{3}$ = $\frac{22+23}{2}$ = 22.5

IQR = $Q_{3}$ - $Q_{1}$ = 22.5 - 16.5 = 6

4 0

2 years ago

What factors of 20 go into 50

xenn [34]

1...2...5...10 are the factors of 20 that go into 50.

5 0

2 years ago