3. A leadership organization of the Cooperative Extension System is a. Boy Scouts. b. FFA c. Girl Scouts. d. 4-H.

A water dispenser has a capacity of 20,000 milliliters. Use the facts to find how much this is in liters .

laila [671]

Answer:

The water dispenser's capacity in liters is 20liters

Explanation:

Given:

A water dispenser capacity = 20,000milliliters

To find

the capacity of the water dispenser in liters

To determine the capacity in liters, we will convert the capacity in ml to liters using the conversion:

1000ml = 1 liter

let the capacity of the water dispenser in Liters = y

$\begin{gathered} 1000ml\text{ = 1 L} \\ 20000ml\text{ = y} \\ cross\text{ multiply:} \\ y(1000)\text{ = 1\lparen20000\rparen} \\ 1000y\text{ = 20000} \end{gathered}$ $\begin{gathered} divide\text{ both sides by 1000:} \\ y\text{ = }\frac{20000}{1000} \\ y\text{ = 20} \end{gathered}$

The water dispenser's capacity in liters is 20liters

5 0

1 year ago

When CA= 3x-1 and SR=5x+4, what is CA?

avanturin [10]

Answer:

CA=17

Step-by-step explanation:

From given picture we see that A and C are the mid points of sides QR and QS respectively.

We know that line joining mid points of the two sides of triangle is always half of the length of the third side.

So that means:

2*CA=SR

2(3x-1)=5x+4

6x-2=5x+4

6x-5x=4+2

x=6

plug value of x into CA=3x-1

CA=3*6-1=18-1=17

Hence final answer is CA=17

8 0

3 years ago

15 = 2c + 7 Solve for c

DaniilM [7]

Step-by-step explanation:

15=2c+7

15-7=2c

8=2c

8/2=c

4=c

c=4

5 0

3 years ago

Read 2 more answers

Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05. He has 7 more nickels than dimes. How many quarters does War

alexdok [17]

7 Quarters

20 nickels

13 dimes

5 0

3 years ago

What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

Equation :-

$\implies log_e {(x^2-25)}= 0$