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Liula [17]
3 years ago
13

Solve for x please help (show ur work)

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

x = -3

Step-by-step explanation:

12 - 4x - 5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from both sides

12 - 12 - 9x = 39 - 12

-9x = 27

Divide both sides by -9

-9x/-9 = 27/-9

x = -3

Zanzabum3 years ago
3 0

Answer:

x = -3

Step-by-step explanation:

12 -4x-5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from each side

12-9x-12 = 39-12

-9x = 27

Divide by -9

-9x/-9 = 27/-9

x = -3

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In the system shown below, what are the coordinates of the solution that lies in quadrant I?
Arisa [49]

Answer:

(4,3)

Step-by-step explanation:

Given

x^2+y^2=25

x-y^2=-5

In order to solve the equations, from equation 2 we get

-y^2= -5-x

y^2=5+x

Putting the value of y^2 in equation 1

x^2+5+x=25

x^2+5-25+x=0

x^2+x-20=0

x^2+5x-4x-20= 0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

So

x+5=0  x-4=0

x=-5   x=4

Now for x=-5

x^2+y^2=25

(-5)^2+y^2=25

25+y^2=25

y^2=25-25

y^2=0

so Y=0  

And for x = 4

x^2+y^2=25

(4)^2+y^2=25

16+y^2=25

y^2=25-16

y^2=9

y= ±3

So the solution to the system of equations is

(-5,0) , (4,3), (4,-3)

The only solution that belongs to first quadrant is (4,3)

4 0
4 years ago
Read 2 more answers
After 3 years, a $1,500 investment is worth $1,680. What is the interest rate on the investment?
hoa [83]

Answer:

0.04

Step-by-step explanation:

1680=1500+1500x3xr

1680-1500=1500x3xr

r=180/4500

r=0.04

7 0
3 years ago
Read 2 more answers
How to simplify 6 +8b^2 +3b -6 - 10b^2
kozerog [31]

Answer:

-2b^2+3b

Step-by-step explanation:

You just have to add like terms, which is the single numbers, the numbers with just the variables, and the numbers with variables that are squared.

5 0
3 years ago
21....................
Mumz [18]

Answer:

The answer is (b) ⇒\frac{d^{5} }{2\sqrt{c} }

Step-by-step explanation:

∵ \frac{\sqrt{c^{2}d^{6}}}{\sqrt{4c^{3}d^{-4}}}

∵ √x² = x ⇒ that means to cancel the square root divide

  the power by 2

∴ \sqrt{c^{2}d^{6}}=cd^{3}

∵ √4 = 2 ⇒ √2×2 = √2² = 2

∵ √c³  = c^{\frac{3}{2}}

∴ \sqrt{4c^{3}d^{-4}}=2c^{\frac{3}{2}}d^{-2}

∴ \frac{cd^{3}}{2c^{\frac{3}{2}}d^{-2}}

∵ In the same base with multiplication we add the power,

  in same base with division we subtract the power

∴ \frac{1}{2}c^{1-\frac{3}{2}}d^{3-(-2)}=\frac{1}{2}c^{\frac{-1}{2}}d^{5}=

  \frac{d^{5}}{2c^{\frac{1}{2}}}=\frac{d^{5}}{2\sqrt{c}} ⇒  c^{\frac{1}{2}}=\sqrt{c}

∴ The answer is (b) ⇒ \frac{d^{5}}{2\sqrt{c}}

8 0
4 years ago
Read 2 more answers
The areas of two circles are 36(pi) and 64(pi). What is hte ratio of the diameters? of the circumferences?
jarptica [38.1K]
2,304 because if you multiply 36 x 64 is 2,304 if not multiply 2,304 x 36 x 64 and then divide the answer by 36 & 64 the it should be 2,304
3 0
3 years ago
Read 2 more answers
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