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Liula [17]
3 years ago
13

Solve for x please help (show ur work)

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

x = -3

Step-by-step explanation:

12 - 4x - 5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from both sides

12 - 12 - 9x = 39 - 12

-9x = 27

Divide both sides by -9

-9x/-9 = 27/-9

x = -3

Zanzabum3 years ago
3 0

Answer:

x = -3

Step-by-step explanation:

12 -4x-5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from each side

12-9x-12 = 39-12

-9x = 27

Divide by -9

-9x/-9 = 27/-9

x = -3

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Determine the range of the graph
alexandr402 [8]
Answer: Range: [0, 5]
8 0
3 years ago
Which expression is equivalent to 8a + 14?<br> 2(2a + 12)<br> 4(4a + 10)<br> 4(2a+8)<br> 2(4a +7)
inessss [21]

Answer is D, 2(4a + 7.)

A is equivalent to 4a + 24.

B is equivalent to 16a + 40.

C is equivalent to 8a + 32.

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7 0
3 years ago
en un colegio mixto hay x estudiantes distribuidos en c cursos. Si hay m niños por curso, ¿Cuantas niñas hay en el colegio?
Tomtit [17]

La ecuación que nos dice cuantas niñas hay en el colegio es:

A = x - c*m

¿Como encontrar una expresión para la cantidad de niñas?

Sabemos que hay un total de x estudiantes, definimos las variables:

  • A = cantidad total de niñas
  • B = cantidad total de niños.

Entonces tenemos A + B = x

Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.

Entonces c por m es igual a la cantidad total de niños:

c*m = B

Reemplazando esto en la ecuación de arriba podemos obtener:

A + c*m = x

A = x - c*m

Esta es la ecuación que nos da el numero total de niñas en el colegio.

Sí quieres aprender más sobre ecuaciones, puedes leer:

brainly.com/question/18168483

4 0
2 years ago
The graph shows the feasible region for the system with constraints:
Dimas [21]

Answer:

The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

The minimum value of the objective function C is 125

Step-by-step explanation:

* Lets look to the graph to answer the question

- There are 3 inequalities

# y ≤ 15 represented by horizontal line (purple line) and cut the

  y-axis at point (0 , 15)

# x + y ≤ 25 represented by a line (green line) and intersected the

  x-axis at point (25 , 0) and the y- axis at point (0 , 25)

# x + 2y ≥ 30 represented by a line (blue line) and intersected the

  x-axis at point (30 , 0) and the y-axis at point (0 , 15)

- The three lines intersect each other in three points

# The blue and purple lines intersected in point (0 , 15)

# The green and the purple lines intersected in point (10 , 15)

# The green and the blue lines intersected in point (20 , 5)

- The three lines bounded the feasible region

∴ The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

- To find the minimum value of the objective function C = 4x + 9y,

  substitute the three vertices of the feasible region in C and chose

  the least answer

∵ C = 4x + 9y

- Use point (0 , 15)

∴ C = 4(0) + 9(15) = 0 + 135 = 135

- Use point (10 , 15)

∴ C = 4(10) + 9(15) = 40 + 135 = 175

- Use point (20 , 5)

∴ C = 4(40) + 9(5) = 80 + 45 = 125

- From all answers the least value is 125

∴ The minimum value of the objective function C is 125

6 0
3 years ago
Read 2 more answers
Simplify the expression: <br> r -3 -r
Ymorist [56]

Answer:

-3

Step-by-step explanation:

Combine the opposite terms in  r  −  3  −  r .

8 0
2 years ago
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