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Vlad1618 [11]
3 years ago
12

What is the answer to (p-q)(2)=

Mathematics
1 answer:
kozerog [31]3 years ago
7 0

Answer:

2p - 2q

Step-by-step explanation:

(p-q)(2)

Multiply both p and -q by 2

2p - 2q

This is as simplified as this equation can get, hope this helps :)

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The dimensions of a wading pool shaped like a rectangular prism are shown below. What is the volume of the pool?
sergey [27]

Answer:

i believe its b

Step-by-step explanation:

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3 years ago
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In a unit circle, ø = 270º. Identify the terminal point and sin ø.
larisa [96]

Answer:

Terminal point (0, -1); sin Ø = -1 ⇒ A

Step-by-step explanation:

In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis

  • The terminal point on the positive part of the x-axis is (1, 0),which means Ф = 0° or 360° and cosФ = 1, sinФ = 0
  • The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
  • The terminal point on the negative part of the x-axis is (-1, 0),which means Ф = 180° and cosФ = -1, sinФ = 0
  • The terminal point on the negative part of the y-axis is (0, -1),which means Ф = 270° and cosФ = 0, sinФ = -1

In a unit circle

∵ Ф = 270°

→ By using the 4th rule above

∴ The terminal point is (0, -1)

∴ sinФ = -1

∴ Terminal point (0, -1); sin Ø = -1

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Write 14:56 in its simplest form
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Answer:2:8

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divide everything by 7

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What is the value of x 12x-18 5x+59
Alex17521 [72]

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11

Step-by-step explanation:

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I don't know how to do this please help explain how to do it aswell as give the answer so i understand
Zinaida [17]

<u>We are given:</u>

The function: y = -16t² + 64

where y is the height from ground, t seconds after falling

<u>Part A:</u>

when the droplet would hit the ground, it's height from the ground will be 0

replacing that in the given function:

0 = -16t² + 64

16t² = 64                          [adding 16t² on both sides]

t² = 4                                [dividing both sides by 16]

t = 2 seconds                  [taking square root of both sides]

<u>Part B:</u>

for second droplet,

height from ground = 16 feet

time taken = t seconds

acceleration due to gravity = 10 m/s²

initial velocity = 0 m/s

h = ut + (1/2)at²                 [second equation of motion]

16 = (0)(t) + (1/2)(10)(t²)

16 = 5t²

t² = 16/5

t = 1.8 seconds (approx)

Therefore, the second droplet takes the least amount time to hit the ground

4 0
3 years ago
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