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2 years ago

Please Help I'm not really good at math

Mathematics

1 answer:

UkoKoshka [18]2 years ago

3 0

The true statements about the triangles RST and DEF are: (a), (d) and (e)

<h3>How to determine the true statements?</h3>

The statement ΔRST ≅ ΔDEF means that the triangles RST and DEF are congruent.

This above implies that:

The triangles can be mapped onto each other by rigid transformations such as reflection, translation and rotation
The transformation does not include dilation
Corresponding sides are congruent

The above means that the possible true statements are: (a), (d) and (e)

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A gas pump measures volume of gas to the nearest 0.01 gallon. Which measurement shows an appropriate level of precision for the

PSYCHO15rus [73]

Answer:

12.3 Gallons

Step-by-step explanation:

Options of the question:-

Option A. 12.33 gallons

Option B. 10 gallons

Option C. 12 gallons

Option D. 12.3 gallons

Option D is the answer :-

As the least count or zero error is 0.1 so it can measure only upto one decimal place so answer will be 12.3

5 0

3 years ago

Help

mina [271]

"A dozen eggs and a dozen jellybeans" is the one comparison among the following choices given in the question that a teacher would most likely use for describing a mole. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.

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3 years ago

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What is 5-2+(9÷1)×9+0

Anna [14]

The answer is 84 because of process priority

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3 years ago

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I need help with this problem

serious [3.7K]

i’m not sure imma look stuff up and get back to you tho

3 0

3 years ago

Use calculus to find the largest possible area for a rectangular field that can be enclosed with a fence that is 500 meters long

rewona [7]

Let $x$ and $y$ be the sides of the rectangle. The perimeter is given to be 500m, so we are maximizing the area function $A(x,y)=xy$ subject to the constraint $2x+2y=500$ .

From the constraint, we find

$2x+2y=500\implies x+y=250\implies y=250-x$

so we can write the area function independently of $y$ :

$A(x,y)=\hat A(x)=x(250-x)=250x-x^2$

Differentiating and setting equal to zero, we find one critical point:

$\dfrac{\mathrm d\hat A(x)}{\mathrm dx}=250-2x=0\implies x=125$

which means $y=250-125=125$ , so in fact the largest area is achieved with a square fence that surrounds an area of $A(125,125)=125^2=15625\text{ m}^2$ .

7 0

3 years ago