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3 years ago

7

Which experiment would fit a binomial model?

1 answer:

MrMuchimi3 years ago

3 0

B.rolling a die I hope this helped

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%3D%20%5Cfrac%7Bx%20-%204%7D%7B3%7D" id="TexFormula1" title="\frac{5}{

valentina_108 [34]

Step-by-step explanation:

$\frac{5}{2} = \frac{x - 4}{3}$

$3 \times \frac{5}{2} = \frac{x - 4}{3}$

$\frac{3}{1} \times \frac{5}{2} = \frac{x - 4}{3}$

cross multiplication

$\frac{6 \times 5}{2} = \frac{x - 4}{3}$

$15 = \frac{x - 4}{3}$

$15 \times 3 = x - 4$

$45 + 4 = x$

$49 = x$

4 0

3 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

I’ll give 50 points if you can help

lbvjy [14]

Answer:

Simplifying

5x + x = 54

Combine like terms: 5x + x = 6x

6x = 54

Solving

6x = 54

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.

x = 9

Simplifying

x = 9

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Hank is throwing a surprise party. The party costs $20 per person. Create an equation and graph to represent the relationship be

o-na [289]

Answer:

10 people,200 dollars. 20 people,400 dollars.100 people,2000 dollars.300 people,6000 dollars.

6 0

3 years ago

In a school, 4/5 of the students study a language.

Svet_ta [14]

Answer:

I agree with Emma

Step-by-step explanation:

above

4 0

2 years ago

Read 2 more answers