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Andreyy89
3 years ago
5

Planes A and B intersect. Vertical plane B intersects horizontal plane A. Point W is on the line where the planes intersect. Ver

tical line m is on the left half of plane A. Horizontal line n intersects line m at point X and line k at point W. Line l is on the lower half of plane B with point Y. Which describes the intersection of plane A and line m? line k line n point X point W
Mathematics
2 answers:
trasher [3.6K]3 years ago
5 0

Answer:

Step-by-step explanation:

i need help 2

Sophie [7]3 years ago
5 0

Answer:

Point X

Step-by-step explanation:

Took the test and got right

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Contact [7]

Answer:

\dfrac{z-y}{a+b}

Step-by-step explanation:

Given expression:

\dfrac{z^2-y^2}{a^2-b^2}\div \dfrac{z+y}{a-b}

Substitute

a^2-b^2=(a-b)(a+b)\\ \\z^2-y^2=(z-y)(z+y)

into the expression:

\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\div \dfrac{z+y}{a-b}\\ \\ \\=\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\times \dfrac{a-b}{z+y}\\ \\ \\=\dfrac{z-y}{a+b}

4 0
3 years ago
Read 2 more answers
. Explain why projectile motion, such as kicking a ball off the top of building, has a curved path. Identify the two forces invo
deff fn [24]

The initial kick is the first force applied to the ball. It sends the ball up into the air (at some angle). If gravity wasn't present, then the ball would go upward forever in a straight line. However, gravity is the second force pulling down on the ball. This explains why the ball hits some peak point or highest point before it is pulled to the ground. Overall, the path the ball takes is a parabolic arch.

In short, the two forces are the initial kick and gravity.

side note: technically air resistance (aka air friction or drag) is a force being applied since the air pushes against the ball to slow it down, but often air resistance is really complicated and beyond the scope of many math courses. So your teacher may want you to ignore air resistance.

Another note: the initial kick is a one time force that only happens at the beginning. Once the ball is in the air, that force isn't applied anymore. In contrast, the force of gravity is always present and always pulling down. It's probably incredibly obvious, but it's worth pointing out this difference.

4 0
3 years ago
If backpack is discounted 10% ib sale for $37.80 what is the original price
taurus [48]

the answer is $34. 36 if I understood your question correctly.
8 0
3 years ago
Mr. Roundtree had 20 tickets. He gave 10 to his family and 8 to his friends.​
Ket [755]
He has two tickets left
5 0
3 years ago
I have this point: (-1,2) and my slope is undefined. How would I write my equation in point-slope form: y - y^1 = m (x -x^1)? Th
tiny-mole [99]

Answer:

x = -1

Step-by-step explanation:

Given the point, (-1, 2), and that the slope is <u><em>undefined</em></u>.

The standard linear equation of vertical lines is <em>x</em> =<em> a</em>, where the x-intercept is (<em>a</em>, 0), and the slope is undefined because all points on the line have the same x-coordinate.  Attempting to solve for the slope of a vertical line using the slope formula, m = (y₂ - y₁)/(x₂ - x₁), will result in a mathematical operation of <u>division by zero</u> (which is an <em>undefined operation</em>).  

Since the slope is <u>undefined</u>, then it is <u>not possible</u> to create a linear equation in either the slope-intercept form, or point-slope form.

Therefore, the equation of a vertical line given the point, (-1, 2) is <em>x</em> = -1.  

7 0
3 years ago
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