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Nastasia [14]
2 years ago
9

3RD ATTEMPT!!! REAL ANSWERS ONLY!!! Draw u + v + w.

Mathematics
1 answer:
svetlana [45]2 years ago
8 0

Answer:

See pic below

Step-by-step explanation:

Use a method of graphic vector addition.

See the picture below.

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A cat has a litter of six kittens. You plan to adopt 2 of the kittens. In how many ways can you choose 2 of the kittens from the
natulia [17]
There are 6 kittens when you're deciding which one you want to pick, so there are 6 ways of chosing one. Then, the number of kittens lowers to 5, so there are 5 ways of picking another. At all, there are 30 ways of chosing 2 kittens out of 6.

3 0
4 years ago
Consider the following argument: If pigs have wings, then pigs can fly. If pigs are lighter than air, then pigs can fly. Pigs ha
Darina [25.2K]

Answer:

a ) If r ⇒ p

    If q ⇒ p

    r ∪ q

    If r∪p ⇒ ¬ r

   ∴ s

b) The argument is invalid

Step-by-step explanation:

The argument is invalid because we do not with precision if b), because we do not have enough information about it, and this is because the previous sentences does not mention information about the donkey. We cannot infer something when we do not have enough information.

3 0
4 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
If you have 20 square pieces of wood describe all the different ways you can make a rectangle by placing them side-by-side
belka [17]
4 by 5

10 by 2

20 by 1

You can place two squares side by side

Technically a square is a rectangle so that counts as a rectangle
8 0
3 years ago
5 girls spent 3 hours cleaning. Write and solve a division equation to find the total number of hours the girls spent cleaning.
ExtremeBDS [4]
15 by multiple 3*5
hope this helps
3 0
4 years ago
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