Answer:
x+y=3
Assuming that the option 1 and 2 dont mean anything
9514 1404 393
Answer:
D) y - 2 = 5/7(x - 7)
Step-by-step explanation:
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
The given answer choices are written in point-slope form, so we can see they expect the line to go through one of the points (-7, -2), (7, 3), or (7, 2). Of these, we note that only point (7, 2) is on the line. (eliminates choices A, B, C)
To confirm that choice D is the correct choice, we can look at the slope between the y-intercept of (0, -3) and the point (7, 2). That is ...
m = (y2 -y1)/(x2 -x1)
m = (2 -(-3))/(7 -0) = 5/7
So, the equation of the line is ...
y -2 = 5/7(x -7)
Answer:
(4, -2)
Step-by-step explanation:
Xb = 1 + (1-(-2)) = 1+3 = 4
Yb = 0 + (0-2) = 0-2 = -2
point B (4, -2)
Complete Question
The complete question is shown on the first uploaded image
Answer:
The sales level that is the cut-off between quarters that are considers as "failure" and those that are not is evaluated as

Step-by-step explanation:
From the question we are told that the
Mean is 
Standard deviation is 
Let Y be the random variable that denotes the sales made quarterly among health care information system
The normal distribution for this data is mathematically represented as
~ N 
From the question we are told that a quarter is consider a failure by the company if the sales level that quarter in the bottom 10% of the of all quarterly sales
So
The the Probability of obtaining quarterly sales level that is equal to 10% of all quarterly sale (It is not below 10%) is mathematically represented as
![P[Y < y ] = 0.10](https://tex.z-dn.net/?f=P%5BY%20%3C%20y%20%5D%20%3D%200.10)
This can be represented as a normal distribution in this manner
![P [ \frac{Y- \mu}{\sigma } < \frac{y -\mu}{\sigma} ] = 0.10](https://tex.z-dn.net/?f=P%20%5B%20%5Cfrac%7BY-%20%5Cmu%7D%7B%5Csigma%20%7D%20%20%3C%20%5Cfrac%7By%20-%5Cmu%7D%7B%5Csigma%7D%20%5D%20%3D%200.10)
Where
~
{This mean that this equal to the normal distribution between 0, 1 which is the generally range of every probability }
Therefor we have
![P[Z < \frac{y- 8}{1.3} ]](https://tex.z-dn.net/?f=P%5BZ%20%3C%20%5Cfrac%7By-%208%7D%7B1.3%7D%20%5D)
The cumulative distribution function for a normal distribution of y is mathematically represented as
![\phi [\frac{y- 8}{1.3} ] = 0.10](https://tex.z-dn.net/?f=%5Cphi%20%5B%5Cfrac%7By-%208%7D%7B1.3%7D%20%5D%20%3D%200.10)
This is because a cumulative distribution function of a random value Y or a distribution of Y evaluated at y is the probability that Y will take will take a value that is less or equal to y

Calculating the inverse of the cumulative distribution function value of 0.10 which is negative the the critical value(Critical values determine what probability a particular variable will have when a sampling distribution is normal or close to normal.) of 0.01
![\phi ^{-1}(0.10) =- [1 - \frac{0.10}{2}]](https://tex.z-dn.net/?f=%5Cphi%20%5E%7B-1%7D%280.10%29%20%3D-%20%5B1%20-%20%5Cfrac%7B0.10%7D%7B2%7D%5D)




Answer:
B) 1,231 in3
Step-by-step explanation:
V = pi * r^2 * h
V = 3.14 * (14 in.)^2 * 2 in.
V = 1230.88 in.^3
Answer: B) 1,231 in3