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marta [7]
3 years ago
5

Please help 3 x + 1 ≤ − 2 OR 3 x + 1 > 5

Mathematics
1 answer:
KengaRu [80]3 years ago
8 0
First one: x <= -1

Second one: x > 4/3

Since you logically OR them together, the answer will be simply the combination of them two:

x <=-1 or x> 4/3
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When solving for y in a equation what is the answer to 5x-3y=21​
masha68 [24]

Answer:

y=53x-7

Step-by-step explanation:

5x-3y=21

-3y=-5x+21

divide by 3

y=5/3x-7

4 0
3 years ago
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ary Stevens earns $6 an hour at her job and is entitled to time-and-a-half for overtime and double time on holidays. Last week s
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Todea what did one pencil say to another mathematics algebra order of operations answer
Serjik [45]
Part 1

6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)}  \\  \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\  \\ =3



Part 2

7-8\div4(3^2-1)=7-8\div4(9-1) \\  \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\  \\ =6  \frac{1}{2} = \frac{13}{2}



Part 3

2-2(2-5)^2+3^2=2-2(-3)^2+9 \\  \\ =2-2(9)+9=2-18+9=-7



Part 4

(5^2-9\cdot3)^2-11=(25-27)^2-11 \\  \\ =(-2)^2-11=4-11=-7



Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



Part 10

7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



Part 11

3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

18+6\div3(2^2+5)=18+6\div3(4+5) \\  \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\  \\  =18 \frac{2}{9}
8 0
3 years ago
12.
g100num [7]

Answer:

Step-by-step explanation:

tan^{-1} (\frac{\sqrt{3} }{3} )=x\\tan x=\frac{\sqrt{3} }{3} =tan (\frac{\pi}{6} )\\x=\frac{\pi}{6}

7 0
3 years ago
Plsss hellpppp 14 and 15 plsssssss
Lesechka [4]

Answer:

14). 2nd quadrant

15). 1st quadrant

Step-by-step explanation:

14).Coordinates of a point → J(-8, -12)

    Coordinates of the new point J' after reflection of x-axis will follow the rule,

    (x, y) → (x, -y)

    Coordinates of J' → (-8, 12)

    Therefore, point J' will lie in 2nd quadrant.

15). Coordinates of a point → W(-6, 7)

    Rule for the rotation by 90°clockwise about the origin,

    (x, y) → (y, -x)

    Coordinates of point W → (-6, 7)

    Following this rule,

    W(-6, 7) → W'(7, 6)

    Therefore, point W' will lie in the first quadrant.

7 0
3 years ago
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