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2 years ago

Please help 3 x + 1 ≤ − 2 OR 3 x + 1 > 5

1 answer:

8 0

First one: x <= -1

Second one: x > 4/3

Since you logically OR them together, the answer will be simply the combination of them two:

x <=-1 or x> 4/3

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Match each step with the correct expression to factor s2 + 78 + 6 by using the decomposition method.

Vinvika [58]

Answer:

did u got the answer?

Step-by-step explanation:

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2 years ago

Need help with R3, R4, S5

marissa [1.9K]

Answer:

R3 Theorem: If parallel lines are cut by a transversal, then alternate interior angles are congruent.

R4 Theorem: Congruence of segments is reflexive.

S5 ΔABC ≅ ΔCDA

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2 years ago

Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always

DIA [1.3K]

Answer:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

8 0

2 years ago

Read 2 more answers

Can someone answer it

Troyanec [42]

Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it.

3 0

3 years ago

In triangle abc, cos A= -0.6. Find A and Tan A

Tresset [83]

Answer:

Part 1) $A=126.87^o$

Part 2) $tan(A)=-\frac{4}{3}$

Step-by-step explanation:

we have

$cos(A)=-0.6$

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

$cos(A)=-0.6$

using a calculator

$A=cos^{-1}(-0.6)=126.87^o$

step 2

Find the sin(A)

we know that

$sin^2(A)+cos^2(A)=1$

substitute the value of cos(A)

$sin^2(A)+(-0.6)^2=1$

$sin^2(A)=1-0.36$

$sin^2(A)=0.64$

$sin(A)=0.8$

step 3

Find tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{0.8}{-0.6}$

Simplify

$tan(A)=-\frac{4}{3}$

5 0

2 years ago