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Inessa [10]
2 years ago
7

George and Paul use a metal alloy that is 18.1% copper to make jewelry. How many ounces of an alloy that is 14% copper must be m

ixed with an alloy that is 23% copper to form 90 ounces of the desired alloy?
Mathematics
1 answer:
ella [17]2 years ago
7 0

Answer:

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

Step-by-step explanation:

Each ounce of the 14% copper contains 0.14 ounce of pure copper.

Each ounce of the 23% copper contains 0.23 ounce of pure copper.

Each ounce of the 18.1% copper contains 0.181 ounce of pure copper.

Use x ounces of the 14% and y ounces of the 23% to make 90 ounces of 18.1% alloy.

x+y  = 90

y = 90-x

0.14x + 0.23y = 0.181·90

0.14x + 0.23(90-x) = 16.29

0.14x + 20.7 - 0.23x = 16.29

-0.09x + 20.7 = 16.29

4.41 = 0.09x

x = 49

y = 90-x = 41

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

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Tamiku [17]

Answer:

first question is 112, second is 336

Step-by-step explanation:

you only need to do is 84÷3/4=112calories

this is one box of cereal state if you want three

box calories just 3×112

3 0
3 years ago
a small dog’s heart beats about 530,000,000 times during its lifetime, and a large dog’s heart beats about 1.4 times this amount
iren2701 [21]

Answer:

I think the answer is 742,000,000

Step-by-step explanation:

6 0
3 years ago
Ratio of 2:3 white flour to whole wheat flour to total of 10 cups flour
LenaWriter [7]
White flour makes up 2 / (2+3) of the total 10 cups:  2/5 of the total 10 cups.

2/5 times 10 is 4 cups.

You'll need 4 cups white flour and 6 cups whole wheat flour, making a total of 10 cups of flour.
8 0
3 years ago
Ive been having this question for a while "what do you use first PEMDAS or Order of Operations". Well you might say it doesn't m
IgorLugansk [536]

Answer:

Order of Operations was aught at a younger age for those just grasping the idea of multiplication and division. Exposing PEMDAS at a young age would confuse them too much, hence the order of operation groups, addition/subtraction and multiplication/division. So for the second example problem, PEMDAS would be correct because it does involve you to use parentheses as well as exponents to solve for. Very easy to mix up between order of operations and PEMDAS, but just look at it as if Order of operations is a beginner level of PEMDAS.

Step-by-step explanation:

5 0
3 years ago
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
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