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LUCKY_DIMON [66]
2 years ago
6

Given the formula for the gas law: pv = nrt. katie tried to solve for the v variable in order to solve a problem. she rearranged

the formula so that v = pnrt. determine if katie solved the equation correctly. if not, describe what mistake she made and solve the equation for v and justify your steps.
Mathematics
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

Katie made a mistake.   P = (nRT)/P is the correct equation, not V = PnRT

Step-by-step explanation:

The equation for the ideal gas law is PV = nRT, where P is pressure, V is volume, n is the moles of gas, R is the gas constant, and T is the temperature, in Kelvin.

Solving for V:

PV = nRT

V = (nRT)/P

Katie did not solve the equation corretly.  To move V from the left to the right side of the equation, she needed to divide both sides by P:

PV = nRT

PV/V = (nRT)/P

P = (nRT)/P is the correct equation

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Belen has $1.65 deducted from her allowance every time she forgets to do a
zavuch27 [327]

Answer:

9.75

Step-by-step explanation:

1.65 x5 is 8.25 then you add half of 1.65 which is .825 to get 9.75

3 0
2 years ago
A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six
kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

V = Length \times Width \times Height \\\\

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

Width = 3 - 2x \\\\

The length of the shaded region is given by

Length = \frac{1}{2} (5 - 3x) \\\\

So, the volume of the box becomes,

V =  \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V =  \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V =  \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V =  \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

a = 18 \\\\b = -38 \\\\c = 15 \\\\

x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 +  19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\

Volume of the box at x= 1.59:

V =  \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\

Volume of the box at x= 0.53:

V =  \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0
3 years ago
A pet supply store sells a 20-pound bag of dog food $23.44. find the unit price what is the error of 20 divided by 23.44=.85
dimulka [17.4K]
23.44 / 20 = 1.172 rounds to 1.17 per lb <== this is cost per lb...this is telling u how much each lb of dog food costs

20 / 23.44 = 0.85....this is lbs per dollar....this is telling u that u r getting 0.85 lbs for a dollar
4 0
3 years ago
What is the value of x? x−16=8 in simplest form.
Minchanka [31]

x = 24

24 - 16 = 8

Hope this helps

5 0
4 years ago
Read 2 more answers
4. Which of the following represents a function?
Dafna11 [192]
The 3 option
(3,9), (-7,1), (6,12), (-3, -9)
3 0
3 years ago
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