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steposvetlana [31]

2 years ago

10

The half-life of a radioactive kind of antimony is 60 days. If you start with 720 grams of it, how much will be left after 180 d

ays?

2 answers:

dimaraw [331]2 years ago

6 0

HALF-LIFE Equals is 30

Marat540 [252]2 years ago

3 0

The answer would be 90 because it takes 60 days to become a half-life so the the half of 720 is 360 the 180 then 90

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Tom got 7 over 8 pound of honey from a hive. He calculated the quotient of 7 over 8 ÷ 2 over 5. Which statement shows the quotie

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Answer:

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Step-by-step explanation:

if he divides (7/8) / (2/5)

he will get x bottles of honey if each bottle weighs 2/5 pound

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Order the decimals in each from least to greatest<br><br> .178 .084 .009 .2

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.009 , .084, .178, .2

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For the straight line defined by the points ( 3 , 51 ) (3,51) and ( 5 , 87 ) (5,87) , determine the slope ( m m ) and y-intercep

Lerok [7]

Answer:

Intercept = - 3 ; slope = 18

Step-by-step explanation:

Given the points :

(3, 51) ; (5, 87)

x1 =3, y1 = 51, x2 = 5 ; y2 = 87

Slope intercept relation:

y = mx + c

m = slope ; c = intercept ; x and y are x, y vlayes respectively

Slope (m) = (y2 - y1) / (x2 - x1)

Slope (m) = (87 - 51) / (5 - 3)

Slope = 36 / 2

Slope (m) = 18

The intercept c :

m = 18 ; x = 5 ; y = 87

Substitute values into the slope intercept formula :

87 = 18(5) + c

87 = 90 + c

c = 87 - 90

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Intercept = - 3

4 0

2 years ago

If your patient needs 2 tsp of cough syrup at 13:40, how much couch syrup are

bagirrra123 [75]

Answer A: 40 ml
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I took the test

5 0

2 years ago

David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let <em>A</em><em> </em>= 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, <em>b</em>, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, <em>C</em>, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When <em>b </em>= 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, <em>B'</em>, is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

#SPJ1

4 0

1 year ago