Answer:9a^2+18a-72
Step-by-step explanation:
9(a+1)^2-81
9(a+1)(a+1)-81
Open brackets
9(a^2+a+a+1)-81
9(a^2+2a+1)-81
9a^2+18a+9-81
9a^2+18a-72
12/6 + 2/3 + 3/4
MMC of 6, 3 and 4 is 12
So 24+8+9/12 = 41/12 = 3,41 approximately.
Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground
Answer:
Step-by-step explanation:
Notice that the y-component is the same, -2, in these two points. That means y does not change as x changes, and therefore we conclude that the slope of the line connecting the two points is m = rise / run = 0.
-2 - (-2)
Alternatively, use m = -------------- = 0
3 - 13
The value of the slope in question is zero: m = 0
Since it's a linear equation and there's a constant rate (given in the problem), we can choose our x - axis to be the time and the y - axis to be height. We choose it that way because you are going up in the elevator. The more time in the elevator, the higher you go.
Finding this equation uses the point slope formula, y - y₁ = m(x - x₁). It can be done with slope-intercept, y = mx + b too.).
First we need to get the slope of the line. Choose any two points, but be consistent and choose two y points as well as the matching x ones. Here, we use x₁ = 2, x₂ = 4, y₁ = 45, y₂ = 75. Slope, m, is y₂ - y₁ / x₂ - x₁.
m = 75 - 45 / 4 - 2
= 30 /2
= 15
Next, we use the slope of 15 and either of the points to find the linear equation. Choose the same (2, 45) x-y pair above, but any point will work.
y - 45 = 15 (x - 2)
y - 45 = 15x - 30
y = 15x + 15
So the linear equation representing this table us y = 15x + 15.
