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2 years ago

Name two ways you could decrease the potential energy of a bucket full of water sitting

Chemistry

1 answer:

DaniilM [7]2 years ago

7 0

Answer: lift up the bucket or put in on something higher or in turn the bench to a higher position

Explanation: i took the test

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Determine whether each of the examples represents a colligative property or a non-colligative property. boiling point elevation

sleet_krkn [62]

Answer:

boiling point elevation - colligative property

color - non-colligative property

freezing point depression - colligative property

vapor pressure lowering - colligative property

density - non-colligative property

Explanation:

A colligative property is a property that depends on the number of particles present in the system.

Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.

Colour and density do not depend on the number of particles present hence they are not colligative properties.

7 0

3 years ago

Consider the balanced equation below. 4nh3 3o2 right arrow. 2n2 6h2o what is the mole ratio of nh3 to n2? 2:4 4:2 4:4 7:2

KIM [24]

The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.

Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that:

4 moles of NH₃ = produces 2 moles of N₂

Mole ratio NH₃ to N₂ is 2:4.

Hence required mole ratio is 2:4.

To know more about mole ratio, visit the below link:
brainly.com/question/504601

3 0

3 years ago

Personal eyeglasses provide as much protection as Group of answer choices splash proof chemical goggles a face shield safety gla

MArishka [77]

Answer:

none of the above

Explanation:

6 0

3 years ago

1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en

Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

$n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles$

$n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles$

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

$n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles$