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malfutka [58]
2 years ago
12

Which two substances are reactants in the following chemical equation?

Chemistry
1 answer:
krok68 [10]2 years ago
4 0
Both A and D
Because these compunds of reactant and the compounds of the product . The reactant goint to equation
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State one advantage of using solar energy instead of burning fossil fuels to produce thermal energy for your home
Pachacha [2.7K]
Solar energy will not run out (unless the sun burns out), but the supply of fossil fuels we use is slowly depleting. Burning fossil fuel also releases greenhouse gas into the air, which is bad for the atmosphere.
4 0
2 years ago
When 3.0 grams of H2 is reacted with excess C at constant pressure, the reaction forms CH4 and releases 53.3 kJ of heat. C(s) +
Murrr4er [49]

Answer:

THE ENTHALPY OF REACTION IN KJ/MOL OF CH4 IS 7.07 KJ/MOL.

Explanation:

Mass of H2 = 3 g

Molar mass of H2 = 2 g/mol

Heat released = 53.3 kJ

Equation of the reaction:

C(s) + 2H2(g) -------> CH4(g)

First:

Calculate the number of moles of H2 that was used:

Number of moles = mass / molar mass

Number of moles = 3g / 2g

Number of moles = 1.5 moles

So therefore, when 53.3 kJ of heat was released from the reaction, 1.5 moles of hydrogen was used.

From the equation of the reaction, one mole of carbon reacts with two moles of hydrogen to form one mole of methane.

For 3 g of hydrogen, 1.5 mole of hydrogen is involved.

It means:

1.5 moles of hydrogen reacts with 0.75 moles of carbon and produces 0.75 moles of methane. This is so because the reaction occurs in 1: 2: 1 in respect to carbon, hydrogen and methane respectively.

So we can say that the production of 0.75 mole of methane will evolve 53.3 kJ of heat.

0.75 mole of methane releases 53.3 kJ of heat.

1 mole of methane will release ( 53.3 kJ * 1 / 0.75 )

= 71.0666 kJ of heat

In conclusion, the enthalpy of the reaction in kJ/ mole of CH4 is 71.07 kJ/mol.

7 0
3 years ago
Glven 4.62 mol of sodium hydroxide, NaOH, how many grams are present?
Vaselesa [24]
1 mole is equal to 1 moles NaOH, or 39.99711 grams.
Hope this helped
3 0
3 years ago
8
Roman55 [17]

Answer:

305 litres of NO gas will be produced from 916 L of NO₂

Explanation:

Given the balanced equation of the chemical reaction as follows:

3 NO₂ (g) + H₂O( l) —— 2 HNO₃ (l) + NO (g)

Under standard conditions, 3 moles of No₂ will react with 1 mole of water to produce 1 mole of NO gas.

Molar volume of a gas at STP is 22.4 L

Number of moles of NO₂ gas present in 916 L = 916/22.4 = 40.893 moles of NO₂ gas

From the mole ratio of NO₂ to NO in the equation of reaction,

Number of moles of NO that will be produced = 1/3 × 40.893 moles = 13.631 moles of NO gas

Volume of 13.631 moles of NO gas = 13.631 × 22.4

Volume of NO gas produced = 305.334L

Therefore, Volume of NO gas produced from the reaction of 916 L of NO₂ with water = 305 L

5 0
2 years ago
If the average salinity of seawater is 35ppt, how many grams of dissolved salts will 500g of seawater contain?
Mila [183]
<span>17.5 g 35 ppt stands for 35 parts per thousand. So let's convert that to a decimal number by taking 35 and dividing by 1000. 35/1000 = 0.035 Now multiply that number by the number of grams of seawater you have. So 0.035 * 500 g = 17.5 g So you have 17.5 grams of salt when you have 500 grams of seawater.</span>
4 0
3 years ago
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