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3 years ago

Convert 970. mm Hg to atm.

Chemistry

1 answer:

REY [17]3 years ago

5 0

Answer:

1.27632 Atmospheres (atm)

Explanation:

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The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was

Ainat [17]

Answer:

Explanation:

From the given information:

The concentration of metal ions are:

$[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}$

$[Ca^{2+}]=0.007118 \ M$

$[Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}$

$=0.001994 \ M$

Mass of Ca²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}$

= 0.1598 g

Mass of Ca²⁺ = 159.0 mg

Mass of Mg²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}$

= 0.3461 g

Mass of Mg²⁺ = 346.1 mg

5 0

3 years ago

What is the name of this hydrocarbon? 2–methylpentyne 2–dimethylpentene 2,3–dimethylpentane 3,2–dimethylpentane

Phantasy [73]

<span>on plato it's 2,3–dimethylpentane

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6 0

3 years ago

The central core of an atom is called the __?

PilotLPTM [1.2K]

Answer: Atomic Nucleus!

Explanation: All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge.

(Yes, it was from google.)

6 0

3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

Nata [24]

Answer:

The correct answer is option B.

Explanation:

$3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2$

Moles of $NBr_3$ = 40 mol

Moles of NaOH = 48 mol

According to reaction, 3 moles of NaOH reacts with 2 moles $NBr_3$

Then ,48 moles of NaOH will reacts with:

$\frac{2}{3}\times 48 mol=32 mol$ of $NBr_3$

Then ,40 moles of $NaBr_3$ will reacts with:

$\frac{3}{2}\times 40 mol=60 mol$ of NaOH

As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.

Moles left after reaction = 40 mol - 32 mol = 8 mol

Hence, the $NBr_3$ is an excessive reagent.

6 0

3 years ago

Read 2 more answers

16. The concentration of a solution of potassium hydroxide is determined by titration with nitric

____ [38]

Answer:

$M_{base}=0.709M$

Explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

$KOH+HNO_3\rightarrow KNO_3+H_2O$

We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

$n_{acid}=n_{base}$

That in terms of molarities and volumes is:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, solving the molarity of the base (KOH), we obtain:

$M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} =\frac{0.498M*42.7mL}{30.0mL}\\ \\M_{base}=0.709M$

Regards.

3 0

3 years ago