Predators are the consumers
Answer:
100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.
Explanation:
In the given question it is mentioned that
S1=50%
V2=250ml
S2= 20%
We all know that
V1S1=V2S2
∴V1= V2×S2÷S1
∴V1= V2S2×1/S1
∴V1= 250×20÷50
∴V1= 100ml
Answer:
W.K.T molar mass of Cuso4.5H2O = 159.609 + 90 = ~250. Mass of water of crystallization = 5 * 18 = 90. Percentage = 90/250 * 100= 36%.
Answer:
0.150 M
Explanation:
The molarity of the solution can be calculated using the formula;
C1V1 = C2V2
Where; C1 = initial concentration of solution
C2 = final concentration of solution
V1 = volume of initial solution
V2 = volume of final solution
According to this question, C1 = 0.200M, C2 = ?, V1 = 75mL, V2 = 100.0mL
Hence,
C1V1 = C2V2
0.200 × 75 = C2 × 100
15 = 100C2
C2 = 15/100
C2 = 0.150M
Therefore, the molarity of the final KCl solution is 0.150M
Answer:
818.6 KJ/mol
Explanation:
2Al(s) + 3H2O(l) → Al2O3(s) + 3H2(g)
∆H=∆Hp-∆Hr
∆H=(1(∆HAl2O3)+3(∆HH2))-(2(∆HAl)+3(∆HH2O))
∆H=((-1676.0 KJ/mol)+3(0 KJ/mol))-(2(0 KJ/mol)+3(-285.8 KJ/mol))
∆H=-818.6 KJ/mol
