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2 years ago

Which of the following is true for the relation f(x)-x^2+8

Mathematics

1 answer:

neonofarm [45]2 years ago

3 0

Answer: A

Step-By-Step Explanation: if n is greater than or equal to 2 is an add integer then the domain of: f(x)-x^2+8 is the solution to the inequality 2+8 greater than or equal to 0. which of the following statements is true?

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The diagram shows a circular pond, of radius r metres, surrounded by a circular path.The circular path has a constant width of 1

Alenkasestr [34]

The formula for calculating the area of a circle is expressed as;

A = πr²

Area of the pond = πr²
Area of the path = Area of the path + pond - area of pond

Area of path = π(r+1.5)² - πr²

Since the area of the path is equal to the area of the pond, hence;

π(r+1.5)² - πr² = πr²

Add πr² to both sides

π(r+1.5)² - πr² + πr² = πr² + πr²

π(r+1.5)² = 2πr²

(r+1.5)² = 2r²

Expand the parenthesis

r²+3r + 2.25 = 2r²

r²+3r + 2.25 - 2r² = 0

-r² + 3r + 2.25 = 0

r² - 3r - 2.25 = 0

Multiply through by 2

2r² - 6.0r - 4.5 = 0

This proves the required equation

Learn more on area of composite figures here: brainly.com/question/15981553

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3 years ago

Answer question 4 pls for math

brilliants [131]

Answer:

Rule: y = 2x

m = 2

b = 0

Step-by-step explanation:

(17, 34) and (22, 44)

Slope:

m=(y2-y1)/(x2-x1)

m=(44-34)/(22-17)

m= (10)/5

m = 2

Slope-intercept:

y - y1 = m(x - x1)

y - 34 = 2(x - 17)

y - 34 = 2x - 34

y = 2x

y = mx + b

y = 2x

b = 0

3 0

3 years ago

It takes Karl 6 hours to drive 372 miles. If he drives at a constant speed during the 6 hours, what is his unit rate? At this ra

Vikki [24]

He drives 62 miles per hour.
And yes, you are right, (496 miles after 8 hours)

5 0

3 years ago

What is the surface area of the right cone below?

olga55 [171]

Answer:

54 is anwer.

please mark me brainliest and follow me my friend.

because 54 is correct answer.

4 0

3 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0. What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

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3 years ago

Read 2 more answers