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stellarik [79]
1 year ago
10

4/ 20÷16 = ____________ plsss help fast plsss really need help fast

Mathematics
2 answers:
Pachacha [2.7K]1 year ago
5 0

__________________________________

\sf\red{ANSWER}

  • 0.0125

Hope it helps (≡^∇^≡)

__________________________________

nexus9112 [7]1 year ago
3 0
0.0125 the answer I calculated it
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\left( \dfrac{-2 + 3}{2}, \dfrac{2 + 0}{2} \right) = \left( \dfrac 1 2, 1 \right)

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Help ASAP please!!!!!
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Which of the following statements describe the graphs of the solution set flr this inequality select two that apply
Helga [31]

Answer:

1st . The shaded region of the graph ....

2nd. The graph line is solid.

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. Since y is greater or<u> equal</u>, the line is solid. If y was only greater the line would have been dotted.

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3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
What are the steps to graphing a linear equation?
chubhunter [2.5K]

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